Slide G

ad-work [718]

F - 3/4 = 5/6
Add 3/4 to both sides to get
F = 5/6 + 3/4 = 19/12

5 0

3 years ago

Two trains leave the station at the same time, one heading west and the other east. The westbound train travels at 80 miles per

Deffense [45]

Answer:

1.4 hour, or 1 hr 24 min

Step-by-step explanation:

The trains separate at the rate (80 + 90) mph.

Recall that distance = rate times time, or time = distance / rate.

238 mi

Here, the elapsed time is -------------- = 1.4 hr, or 1 hr 24 min

170 mph

3 0

3 years ago

karas jug contains 2 quarts of apple cider.she fills 8 mugs with cider.each mug can hold six three fourths of fluid ounces.how m

bazaltina [42]

So first of all you need to know that in 1 quart there is 31.9995 ounces so since shes says there is 2 quarts lets do the math:)
31.9995 x 2 = 63.999 ounces
now she says she took 8 mugs and filled them up each with 6 and 3/4 ounces. lets do the math:)
6 and 3/4 x 8 = 30 ounces
now lets subtract that from our 2 quarts or 63.999 ounces
63.999 - 30 = 33.999
so we have 33.999 fluid ounces left in the jar:)
hope this helps lol

8 0

3 years ago

What is -7 + 1/3 plz help and thanks

Ugo [173]

Answer:

-6 2/3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes

Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(completing the exam in one hour or less)

P(x < 60)

$P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)$

Calculation the value from standard normal z table, we have,

$P(x < 60) =0.023= 2.3\%$

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

$P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%$