Good job, you got the equations! XD
I'll just help you solve
Multiply the 2nd row by 9
<span>9x+9y=117</span>
<span><span><span>9x+27y=207
</span></span></span>Subtract the 2nd row from the 1st row
<span><span><span>−18y=−90
</span></span></span>Divide both sides by <span>−18</span>
<span><span><span>y=<span><span>−90/</span><span>−18
</span></span></span></span>Two negatives make a positive
<span><span>y=<span><span>90/</span><span>18</span></span></span><span></span></span><span>
y = 5
Substitute 5 into an equation
9x+9(5)=11<span>7
</span>9x+45=11<span>7
</span>Subtract <span>45</span> from both sides
<span><span><span>9x=117−45
</span></span></span>9x=7<span>2
</span>Divide both sides by <span><span>9</span></span>
x = ___
Hope this will help</span></span>
Answer: A circle is 360° all the way around; therefore, if you divide an arc's degree measure by 360°, you find the fraction of the circle's circumference that the arc makes up. Then, if you multiply the length all the way around the circle (the circle's circumference) by that fraction, you get the length along the arc.
Step-by-step explanation:
Answer:
Standard Deviation = 9.1
(Please vote me Brainliest if this helped!)
Step-by-step explanation:
Standard deviation = square root of variance
=
= 9.1
The rhombus has a couple of very interesting properties. The first is that the diagonals meet at 90o angles.
The second is that all the sides are congruent. That's actually the key to the problem (or one of them.
The third is that the diagonals are line segments that bisect the angles where the vertex of the angle is.
So just to make sure you understand what that last statement means <PKM = <NKM
K is the vertex of angle PKN
Now the really heavy duty stuff about your question.
Given
K is obtuse. Therefore <PKM can't be 16o because MKN would also have to be 16 degrees and together they don't add up to anything over 90o.
So the 16o angle is at <EPK
Remember that the diagonals meet at right angles. <PEK = 90o
Finally all triangles have 180o
< PKE = 180 - 16 - 90 = 74. So to review
<PKE = 74o
<EPK = 16o
<PEK = 90o That's one half the problem.
Moving on to triangle PMN
By the properties of parallel lines and a rhombus and isosceles triangles, that since PKN is bisected (rhombus property) Then PKN = 2* PKM =2*74 = 148o
The angle opposite <PKN is equal to <PKN so <PMN = <PKN
Since PKN = 148 then PMN = 148
Since KPN = 16o then PMN = 16o
Since triangle <PMN is isosceles <PNM = 16o
Summing up
PMN = 148o
MPN = 16o
MNP = 16o
That's both triangles solved. This is a really nice little problem. If you google properties of a rhombus, you will find all the properties I have used proven.
Answer:
(4x)^ 10
Step-by-step explanation: