When p = 12, t = 2, and s=1/6r = 18. If r varies directly with p and inversely with the product of s and t, what is the constant

Question

Pavel [41]

3 years ago

5

When p = 12, t = 2, and s=1/6r = 18. If r varies directly with p and inversely with the product of s and t, what is the constant

of variation?

Mathematics

2 answers:

fgiga [73] · Answer 1 · 2022-03-15T14:21:40+03:00

fgiga [73]3 years ago

7 0

R $\alpha \frac{p}{st}$
r=k $\frac{p}{st}$
18=12 $\frac{k}{1/6*2}$
18=12*3k
k= $\frac{1}{2}$

Dmitry_Shevchenko [17] · Answer 2 · 2022-03-15T13:00:54+03:00

Dmitry_Shevchenko [17]3 years ago

5 0

R α p/(st)

r = kp/(st)

Where k = constant of proportionality

r = 18, p = 12, t = 2 , s = 1/6

r = kp/(st)

18 = k*12/((1/6)*2)

18 = 12k /(1/3)

18 = 12*3*k

18 = 36k

18/36 = k

1/2 = k

k = 1/2

Constant of variation = 1/2 = 0.5