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Rudiy27
3 years ago
7

Need help please!! i will mark brainliest to whoever answers correctly <33

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0

Answer:

x = -33

Step-by-step explanation:

To find the midpoint add the two points and divide by 2

(x+27)/2 = -3

Multiply each side by 2

(x+27)/2 *2= -3*2

x+27 = -6

Subtract 27 from each side

x+27-27 = -6 -27

x = -33

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22 is 40% of what number? <br><br> 32 is 20% of what number?
Yuri [45]

Answer:

22 is 40% of what number?

55

32 is 20% of what number?

160

Step-by-step explanation:

If 22 is 40% of a number you can divide 22 by 40 to find what one % would be.

22/40=.55

To find what the whole number is we can multiply that by 100, since we want 100% of the number we have is only 1%.

.55x100=55

Check:

40% of 55= 55x.4=22

Repeat this for the next problem.

32/20=1.6

1.6x100=160

Check:

160x.2=32

4 0
3 years ago
The ratio of girls to boys at a summer camp is 2/3. there are 20 children at the camp. how many girls are there?
g100num [7]
Ratio=  2:3 add them together= 5. 20 divided by 5= 4.
4x2=8
3x4=12
8 girls and 12 boys
8 0
4 years ago
Could someone tell me how i got this wrong?
Ipatiy [6.2K]

Answer:

multiplying is wrong. You were supposed to add. The equation would be 1/4 + m = 2/3. If it was M amount of 1/4's = 2/3 then you would be right but M was supposed to be added on because it was a missing chunk.

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Simplify, brainliest to the most elaborated answer.
xxTIMURxx [149]

Answer:

wait writing on a piece of paper

6 0
3 years ago
a fair coin is flipped. if the flip results in a head, then a fruit is selected from a basket containing 8 apples, 2 bananas, an
Shkiper50 [21]

Solution :

We have given two baskets :

$H_1$ : 8 apples + 2 bananas + 6 cantaloupes = 16 fruits

$H_2$ : 6 apples + 4 bananas = 10 fruits

A fair coin is made to flipped. If the \text{flip} results is head, then the fruit is selected from a basket $H_1$.

If the flip results in tail, then the fruit is selected from the basket $H_2$.

Probability of head P(H) = 1/2

Probability of tail P(T) = 1/2

if given event is :

B = selected fruit is BANANA

We have to calculate : P(T|B)

Probability of banana if the flip results is head P(B|H) = $\frac{2}{16}$

Probability of banana if the flip results is tail P(B|T) = $\frac{4}{10}$

From the Bayes' theorem :

Probability of flip results is tail when selected fruit is BANANA.

$P(T|B) = \frac{P(B|T)\ P(T)}{P(B|T) \ P(T) + P(B|H)\ P(H)}$

            $=\frac{\frac{4}{10} \times \frac{1}{2}}  {\frac{4}{10} \times \frac{1}{2} + \frac{2}{16} \times \frac{1}{2}}$

            $=\frac{\frac{1}{5}}{\frac{1}{5}+\frac{1}{16}}$

            $=\frac{\frac{1}{5}}{\frac{21}{80}}$

            $=\frac{16}{21}$

∴  $P(\ T|B\ )=\frac{16}{21}$

6 0
3 years ago
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