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Kruka [31]
3 years ago
10

If you have one ace what is the probability that you have a second ace

Mathematics
1 answer:
Basile [38]3 years ago
5 0
The way your question is worded, the probability is zero. One ace is not two aces.
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Help!<br> Please and thank you
JulsSmile [24]

Answer:

67.5

67.5

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8 0
3 years ago
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(2.5 x 104) * (8 x 10) =
Romashka-Z-Leto [24]

Answer:

20,800

Step-by-step explanation:

4 0
2 years ago
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What is the solution of 6(3-2x)=54?
notka56 [123]
Hello!

You solve this algebraically

6(3 - 2x) = 54

distribute the 6

18 - 12x = 54

Subtract 18 from both sides

-12x = 36

Divide both sides by -12

x = -3

The answer is -3

Hope this helps!
3 0
3 years ago
Read 2 more answers
Please answer the WHOLE question and explain!
exis [7]

The total weight of candies is unknown. Let x = the total weight of candies.

"One student ate 3/20 of all candies and another 1.2 lb":

The first student ate (3/20)x plus 1.2 lb which is 0.15x + 1.2.

"The second student ate 3/5 of the candies and the remaining 0.3 lb."

The second student ate (3/5)x and 0.3 lb which is 0.6x + 0.3.

Altogether the 2 students ate 0.15x + 1.2 + 0.6x + 0.3.

That was all the amount of candies, so that sum equals x.

0.15x + 1.2 + 0.6x + 0.3 = x

Now we solve the equation for x to find what the total amount of candies was.

0.75x + 1.5 = x

-0.25x = -1.5

x = 6

The total amount of candies was 6 lb.

The first student ate 0.15x + 1.2 = 0.15(6) + 1.2 = 0.9 + 1.2 = 2.1, or 2.1 lb of candies.

The second student ate 0.6x + 0.3 = 0.6(6) + 0.3 = 3.6 + 0.3 = 3.9, or 3.9 lb of candies.

Answer: The first student ate 2.1 lb of candies, and the second student ate 3.9 lb of candies.

7 0
3 years ago
I need help with this
12345 [234]
Are you solving for x and y? 5y + 2(6x) would just be 5y + 12x
6 0
3 years ago
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