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dem82 [27]
1 year ago
9

Determine if the function f(x) = 3x ^ 5 - 9 is even, odd, or neither

Mathematics
1 answer:
o-na [289]1 year ago
6 0

Answer:

the function f is neither even nor odd

Step-by-step explanation:

f(x) = 3x⁵ - 9

we start by calculating f(-x)

f(-x) = 3(-x)⁵ - 9

      = 3(-(x)⁵) - 9   (Since 5 is an odd number then (-x)⁵ = - x⁵)

      = - 3x⁵ - 9

Then

f is not even because f(-x) = - 3x⁵ - 9 ≠ 3x⁵ - 9 = f(x)

f is not odd because f(-x) = - 3x⁵ - 9 ≠ -3x⁵ + 9 = -f(x)

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1, -c/2 &lt; -1.5<br> 2. -y/2 &lt; 6<br> 3. -d/3 &gt; -9
irina1246 [14]

Answer:

um ight if your asking me if there are right i guess they are...

3 0
3 years ago
Which is the slope of the line that passes through the points (3,17)(3,17) and (7,25)(7,25)?
PilotLPTM [1.2K]
The slope is 2, because you subtract the points 3,17 from 7,25 to get 8/4/ Simplify that into 2. 
4 0
3 years ago
Two Parallel lines are cut by a transversal x and a transversal y so that x and y intersect at point Q as shown.
saw5 [17]

Answer:

- Angle 'a' is an alternating exterior angle with one angle in the triangle and therefore congruent to one angle in the triangle formed by lines m, x, and y.

- Angles 'b' and 'c' are vertical angles with the other two angles in the triangle and therefore congruent to two other angles in the triangle

Step-by-step explanation:

Vertical angles are angles that are equal to each other but in opposite direction. The angles b and c have vertical angles on the triangle Q while alternate exterior angles are equal angles that lie on different lanes cutting through an axis.

Angles on a plane can be congruent if they are vertical equals or alternating exterior angles.

8 0
3 years ago
Help please!posted picture of question
Evgen [1.6K]
The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)

The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)

Answer: The system of inequalities would produce the region indicated on the graph is Option B

8 0
3 years ago
What’s 4 to the power of 2 times 3
Eva8 [605]

Answer:

48

Step-by-step explanation:

3 0
3 years ago
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