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Oliga [24]
4 years ago
9

A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpoles shadow is 30 feet at a

certain time of day , how long is the building’s shadow at that time?
Mathematics
2 answers:
MArishka [77]4 years ago
4 0

The building is 300/50 = 6 times as high as the flagpole, so we expect its shadow to be 6 times as long: 6×30 ft = 180 ft.

Westkost [7]4 years ago
3 0

Answer with explanation:

Length of Flagpole =50 foot

Height of Building =300 feet

Length of shadow of Flagpole =30 feet

Let shadow of building = x feet

The shadow of building as well as Flagpole are taken at the same time .So they are proportional to each other.

\frac{\text{Height of Building}}{\text{Length of Flagpole}}=\frac{\text{Height of Shadow of Building}}{\text{Length of Shadow of Flagpole}}\\\\\rightarrow \frac{300}{50}=\frac{x}{30}\\\\\rightarrow x=30 \times 6\\\\\rightarrow x=180

So, Building's Shadow =180 feet

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