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Oliga [24]
3 years ago
9

A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpoles shadow is 30 feet at a

certain time of day , how long is the building’s shadow at that time?
Mathematics
2 answers:
MArishka [77]3 years ago
4 0

The building is 300/50 = 6 times as high as the flagpole, so we expect its shadow to be 6 times as long: 6×30 ft = 180 ft.

Westkost [7]3 years ago
3 0

Answer with explanation:

Length of Flagpole =50 foot

Height of Building =300 feet

Length of shadow of Flagpole =30 feet

Let shadow of building = x feet

The shadow of building as well as Flagpole are taken at the same time .So they are proportional to each other.

\frac{\text{Height of Building}}{\text{Length of Flagpole}}=\frac{\text{Height of Shadow of Building}}{\text{Length of Shadow of Flagpole}}\\\\\rightarrow \frac{300}{50}=\frac{x}{30}\\\\\rightarrow x=30 \times 6\\\\\rightarrow x=180

So, Building's Shadow =180 feet

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ValentinkaMS [17]

Answer:

The length of the ladder is 14.5 ft

Step-by-step explanation:

For a right triangle

sinx = opposite / hypotenuse

Since we know the angle and the opposite side, we can calculate the hypotenuse

sin 64 = 13/ hypotenuse

Multiply each side by the hypotenuse

hypotenuse * sin 64 = 13

Divide by sin 64

hypotenuse = 13/sin 64

hypotenuse=14.4638

Rounding to the nearest tenth

14.5

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3 years ago
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3 years ago
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sashaice [31]

Answer:

W1 = W2 = 50k Joules (assuming W1 and W2 have the same force constant, k)

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Step-by-step explanation:

Work done in stretching a spring is given by 1/2ke^2

Where, k is force constant and e is extension

e1 = 30cm - 20cm = 10cm

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3 years ago
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