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tatiyna
3 years ago
7

Given: (−10,2) and (3,5), the midpoint is???

Mathematics
2 answers:
Rudik [331]3 years ago
5 0

Answer:

M=(−7/2,7/2).

Step-by-step explanation:

Gennadij [26K]3 years ago
3 0

Answer:

\huge{ \boxed{ \sf{( \frac{ - 7}{2}  \:,  \:  \frac{7}{2})}}}

Step-by-step explanation:

\star{ \sf{Let \: the \: points \: be \: A \: and \: B}}

\sf{A( - 10 ,\: 2) \longrightarrow{ \: (x1 \:, y1)}}

\sf{B(3 \:, 5) \:  \longrightarrow} \:  \sf{(x2 \:, y2)}

\underline{ \text{Finding \: the \: midpoint}} :

\boxed{ \sf{Midpoint \:  =  \: ( \frac{x1 + x2}{2}  \: , \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{ - 10 + 3}{2}  \: , \frac{2 + 5}{2} }})

\text{Remember!} :

  • The positive integers are always added and posses the positive ( + ) sign.
  • The negative integers are always added but posses the negative ( - ) sign.
  • The negative and positive integers are always subtracted but posses the sign of the bigger integer.

\mapsto{ \sf{Midpoint = ( \frac{ - 7}{2} , \:  \frac{7}{2} }})

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

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A production process produces 2% defective parts. a sample of 5 parts from the production is selected. what is the probability t
Lana71 [14]

Answer:

Probability of a sample that contains exactly two defective parts is .0037 or .37%

Step-by-step explanation:

As we know if P is the probability of achieving k results in n trials then probability formula is P = \binom{n}{k}p^{K}q^{n-k}

In this formula n = number of trials

                        k = number of success

                        (n-k) = number of failures

                         p = probability of success in one trial

                         q = (1-p) = probability of failure in one trial

In this sum n = 5

                  k = 2

number failures (n-k) = (5-2) = 3

                            p = 2% which can be written as .02

                            q = 98% Which can be written as .98

Now putting these values in the formula

                        P = \binom{5}{2}(.02)^{2}(.98)^{5-2}

                        P = \binom{5}{2}(.02)^{2}(.98)^{3}

                   \binom{5}{2}= 5!/3!2!    

                                              = 5×4×3×2×1/3×2×1×2×1

                                              = 5×2 =10

                                       P = 10×(.02)²×(.98)³

                                          = .0037 or .37%

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3 years ago
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