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2 years ago

Which pair of functions are inverse of each other

Mathematics

1 answer:

natta225 [31]2 years ago

7 0

Answer:

(A)

Step-by-step explanation:

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Convert 6 4/5 to an improper fraction.

Marina86 [1]

6 4/5 as improper fraction is 34/5

5 3/4 as improper fraction is 23/4

3 1/3 by 25/4 is 8/15

14/3 by 3 1/2 is 4/3

3 1/4 by 5 1/2 is 13/22

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2 years ago

Find the length of the missing side. It’s a written response

andre [41]

Using Pythagorean’s theorem, the side length is sqrt(89)

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2 years ago

Read 2 more answers

please help! functions and relations. f(x)= square root of x-4. find the inverse of f(x) and it’s domain.

likoan [24]

ANSWER:

$\:D.\text{ }f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge-4$

STEP-BY-STEP EXPLANATION:

We have the following equation:

$f(x)=\sqrt{x}-4$

The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

$\begin{gathered} x=\sqrt{f^{-1}(x)}-4 \\ \\ \sqrt{f^{-1}(x)}=x+4 \\ \\ f^{-1}(x)=(x+4)^2 \end{gathered}$

The domain would be the range of the original equation, and it would be the range of values that f(x) could take, which was from -4 to positive infinity, that is, f(x) ≥ -4.

Therefore, the domain is x ≥ -4.

So the correct answer is D.

$\:f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge -4$

4 0

8 months ago

Please Help!

JulijaS [17]

Answer: $8865=6000(1+\frac{5\times t}{100})$

Step-by-step explanation:

Given

Liam deposited $P=\$\ 6000$

Rate of interest is $R=5\ \%$

If the amount after t years is $A=\$\ 8865$

Simple interest is given by

$S.I.=\dfrac{P\times R\times t}{100}$

And amount is

$A=P+S.I.$

$A=P(1+\frac{R\times t}{100})$

Substituting values we get

$8865=6000(1+\frac{5\times t}{100})$

$1.4775=1+\frac{5\times t}{100}$

$0.4775\frac{5\times t}{100}$

$5t=47.75$

$t=\frac{47.75}{5}=9.55\ years$

8 0

2 years ago

Paula's Flowers sells 39 arrangements per week. The flower shop down the street sells

Eddi Din [679]

Answer:

50:39

Step-by-step explanation:

The first number in the context always goes first!

4 0

3 years ago