Answer:
ewrwewqetqwrtweq
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
See Discussion below
Discussion:
A function f is even if f(-x) = f(x)
f(x) f(-x) Are they equal?
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-x^8 + 2x^6-5x -(-x)^8 + 2(-x)^6 + 5x No
3 abs(x) - 4 3 abs(-x) -4 Yes
log5 x^2 log5 (-x)^2 Yes
(6x)^ (1/7) (-6x)^(1/7) No
e^(x^2-x) e^( (-x)^2+x) No
(x^8 +5x^2)^(-1) ( (-x)^8 + 5 (-x)^2) ^(-1) Yes
Answers with Yes, above are even functions.
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MrB
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24 marbles in the first group
28 marbles in the second group
f(h(x))= 2x -21
Step-by-step explanation:
f(x)= x^3 - 6
h(x)=\sqrt[3]{2x-15}
WE need to find f(h(x)), use composition of functions
Plug in h(x)
f(h(x))=f(\sqrt[3]{2x-15})
Now we plug in f(x) in f(x)
f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6
cube and cube root will get cancelled
f(h(x))= 2x-15 -6= 2 x-21
