We have to calculate the probability of picking a 4 and then a 5 without replacement.
We can express this as the product of the probabilities of two events:
• The probability of picking a 4
,
• The probability of picking a 5, given that a 4 has been retired from the deck.
We have one card in the deck out of fouor cards that is a "4".
Then, the probability of picking a "4" will be:

The probability of picking a "5" will be now equal to one card (the number of 5's in the deck) divided by the number of remaining cards (3 cards):

We then calculate the probabilities of this two events happening in sequence as:

Answer: 1/12
Answer:
Yes
Step-by-step explanation:
From the origin means from the centre or middle but about a vertex is from a named point.
Answer: Choice C
x intercept is (4,0)
y intercept is (0,2)
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Work Shown:
To find the x intercept, we plug in y = 0 and solve for x
2x+4y = 8
2x+4(0) = 8
2x+0 = 8
2x = 8
x = 8/2
x = 4
We have x = 4 pair up with y = 0. So we have (x,y) = (4,0) as the x intercept.
This is the location where the graph crosses the x axis.
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The y intercept is a similar story, but we use x = 0 to find y.
2x+4y = 8
2(0)+4y = 8
0+4y = 8
4y = 8
y = 8/4
y = 2
The value x = 0 leads to y = 2. This gets us (x,y) = (0,2) as the y intercept.
This is the location where the graph crosses the y axis.
The slope of a function at a point is the value of its derivative there.
... f'(x) = 5·(2x) + 0 = 10x . . . . . . using the power rule: (d/dx)(xⁿ) = n·xⁿ⁻¹
Then
... f'(4) = 10·4 = 40 . . . . . the slope at x=4