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Kaylis [27]
3 years ago
13

1/7-3(3/7n-2/7) combining like terms with rational coefficients. 

Mathematics
2 answers:
laiz [17]3 years ago
7 0

Answer:

Expanding form

\frac{1}{7}-\frac{9}{7}n+\frac{6}{7}

1-\frac{9}{7}n

Step-by-step explanation:

We are given that \frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7})

We have to expand the terms and combine like terms

\frac{1}{7}-\frac{9}{7}n+\frac{6}{7}

Expanding form

\frac{1}{7}-\frac{9}{7}n+\frac{6}{7}

In the given expression like terms are \frac{1}{7}and \frac{6}{7}

\frac{1}{7}+\frac{6}{7}-\frac{9}{7}n

\frac{1+6}{7}-\frac{9}{7}n

\frac{7}{7}-\frac{9}{7}n

1-\frac{9}{7}n

Salsk061 [2.6K]3 years ago
6 0
I think it is 9/7n - 5/7
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According to the Knot, 22% of couples meet online. Assume the sampling distribution of p follows a normal distribution and answe
Ann [662]

Using the <em>normal distribution and the central limit theorem</em>, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

In this problem:

  • 22% of couples meet online, hence p = 0.22.
  • A sample of 150 couples is taken, hence n = 150.

Item a:

The mean and the standard error are given by:

\mu = p = 0.22

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.22(0.78)}{150}} = 0.0338

The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 0.25</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{0.25 - 0.22}{0.0338}

Z = 0.89

Z = 0.89 has a p-value of 0.8133.

1 - 0.8133 = 0.1867.

There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

Item c:

The probability is the <u>p-value of Z when X = 0.2 subtracted by the p-value of Z when X = 0.15</u>, hence:

X = 0.2:

Z = \frac{X - \mu}{s}

Z = \frac{0.2 - 0.22}{0.0338}

Z = -0.59

Z = -0.59 has a p-value of 0.2776.

X = 0.15:

Z = \frac{X - \mu}{s}

Z = \frac{0.15 - 0.22}{0.0338}

Z = -2.07

Z = -2.07 has a p-value of 0.0192.

0.2776 - 0.0192 = 0.2584.

There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

4 0
2 years ago
2a - 7 - 6a = 9<br> Pls help?
slavikrds [6]

Step-by-step explanation:

2a - 7 - 6a = 9

- 4a - 7 = 9

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a = -4

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On one day in January, the temperature in Milwaukee, Wisconsin fell 12°F from the high temperature to a low temperature of -8°F.
tatiyna

Answer:

t = 4

Step-by-step explanation:

you have -8 and twelve you equation is x -12 = -8 so we just have to flip the equation around to make it x = 12 -8 which is easy . You just have to make sure you don't get mixed up while flipping the signs.

5 0
3 years ago
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dusya [7]

Answer: 11/23

Step-by-step explanation:

I used my calculator to convert those fractions into decimal form and found the biggest number. It was about 0.4789.

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Just do each number to they square root
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