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Kaylis [27]
3 years ago
13

1/7-3(3/7n-2/7) combining like terms with rational coefficients. 

Mathematics
2 answers:
laiz [17]3 years ago
7 0

Answer:

Expanding form

\frac{1}{7}-\frac{9}{7}n+\frac{6}{7}

1-\frac{9}{7}n

Step-by-step explanation:

We are given that \frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7})

We have to expand the terms and combine like terms

\frac{1}{7}-\frac{9}{7}n+\frac{6}{7}

Expanding form

\frac{1}{7}-\frac{9}{7}n+\frac{6}{7}

In the given expression like terms are \frac{1}{7}and \frac{6}{7}

\frac{1}{7}+\frac{6}{7}-\frac{9}{7}n

\frac{1+6}{7}-\frac{9}{7}n

\frac{7}{7}-\frac{9}{7}n

1-\frac{9}{7}n

Salsk061 [2.6K]3 years ago
6 0
I think it is 9/7n - 5/7
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Hi there!

Let's solve this problem step by step!
f(x) =  \frac{1}{8} (8 {}^{x})

To find f(3) we must substitute x = 3 into the formula.
f(3) =  \frac{1}{8} (8 {}^{3} )

Now we use PEMDAS (Parenthesis, exponents, multiply, divide, add, subtract) to find our answer.

Work out the exponents inside the parenthesis first.
f(3) =  \frac{1}{8}  \times 512

And finally multiply.
f(3) =  \frac{1}{8}  \times  \frac{512}{1}  =  \frac{512}{8}  = 64

Hence, the answer is D. 64.
~ Hope this helps you!
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