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vagabundo [1.1K]
3 years ago
9

Arthur purchased a 2010 model sedan for $20,000. The dealership offered

Mathematics
1 answer:
JulsSmile [24]3 years ago
3 0

Answer: the answer is $ 17,349.21 APEX

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What is the value of r in the equation 4r − 8 = 5r + 12?<br><br> −20<br> −1<br> 1<br> 20
inn [45]

Answer

r = -20

Step-by-step explanation

4r-8=5r+12

subtract 4r from both sides of the equation

-8=r+12

subtract 12 from both sides of the equation

-20 = r

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3 years ago
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Please show all work with the answers please
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Part A

The angle of elevation of the staire case is given by

Angle\ of\ elevation=\tan^{-1}{ \frac{Vertical\ rise}{landing} } \\  \\ =\tan^{-1}{ \frac{14}{20} }\approx35^o



Part B:

<span>If the landing of each step is changed to 17 inches and the elevation of each step to 21 inches, the new angle of elevation for the staircase is given by

</span><span>Angle\ of\ elevation=\tan^{-1}{ \frac{Vertical\ rise}{landing} } \\  \\ =\tan^{-1}{ \frac{17}{21} }\approx39^o</span>
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help

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Triangle ABC is a right triangle and cos(22.6)
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3 years ago
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
3 years ago
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