Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').)
Write this in cases:
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant.
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0.
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b.
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function.
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x).
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.)
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have.
I hope this helps!
Answer:
A boat would need 21 liters to cover the distance of 84 km.
Step-by-step explanation:
Given
A boat can travel 496 km on 124 liters of fuel.
To determine
How much fuel will it need to go 84 km?
It is stated that:
Distance covered in 124 liters of fuel = 496 km
Thus,
Unit rate = 496 km / 124 liters
= 4 km per liter
Thus,
The distance covered in 1 liter = 4km
In order to determine the distance covered in 84 km, all we need is to divide 84 km by 4.
i.e.
The fuel needed to go 84 km = 84 / 4 = 21 liters
Therefore, a boat would need 21 liters to cover the distance of 84 km.
Answer:
12600 g
Step-by-step explanation:
a kilogram is a thousand grams
(don't forget to include units)
