70 I believe is the correct answer
Answer:
1 1/5 miles per hour
Step-by-step explanation:
3/5 = 0.60
1/2= 0.5 hr
0.60 * 2 = 1.2
1.2 mph = 1 1/5
slope = (25-4)/(30-10)
slope = 21/20
slope =21/20
using point slope form
y-y1 = m(x-x1)
y-4 = 21/20 (x-10)
y = 21/20x -21/2 +4
y = 21/20 x -21/2 +8/2
y = 21/20x -13/2
let x=40
y = 21/20 (40) -13/2
y = 42-13/2
y = 35.5 games
If we round the slope to 1
slope =1
using point slope form
y-y1 = m(x-x1)
y-4 = 1 (x-10)
y = 1x -10 +4
y = x -6
let x=40
y = 40-6
y = 34 games
Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3
A.
B and C are wrong because x is more than or equal to 3.
D is wrong because y is the weight of oranges and cannot be negative.
