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Assoli18 [71]
4 years ago
13

A recent survey of 1000 American women between the ages of 45 and 64 asked them what medical condition they most feared. Of thos

e sampled, 61% said breast cancer, 8% said heart disease, and the rest picked other conditions. By contrast, currently about 3% of female deaths are due to breast cancer, whereas 32% are due to heart disease?a. Construct a 90% confidence interval for the population proportion of women who most feared breast cancer. Interpret.b. Indicate the assumptions you must make for the infer- ence in part a to be valid.
Mathematics
1 answer:
defon4 years ago
7 0

Answer:

Confidence interval for the population proportion of women fearing from breast cancer are 61%

Step-by-step explanation:

Point estimate of the proportion of the population of women who feared from breast cancer is:

β=61%

Standard error of the estimate:

Se= 0.154

Margin of error for 90% confidence interval for the population proportion:

0.254

90% confidence interval for the population proportion will be

(0.5846,0.6354)

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Subtract

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5 0
4 years ago
A perpendicular bisector <br> A congruent angle<br> Congruent line segment <br> Angel bisector
Harlamova29_29 [7]

Answer:

angle bisector

Step-by-step explanation:

4 0
4 years ago
en un maratòn participan corredores de todos los continentes 5/6 de los corredores son europeos se sabe que los americanos son l
Marysya12 [62]

Usando proporciones, se encuentra que 400 africanos han participado.

En total, hay x participantes.

\frac{5}{6} de los corredores son europeos, o sea:

E = \frac{5x}{6}

Los americanos son la dècime parte de los europeos, o sea:

Am = \frac{1}{10}E = \frac{5x}{60} = \frac{x}{12}

Los africanos son la quinta parte de los americanos, o sea:

Afr = \frac{1}{5}Am = \frac{x}{60}

En la carrera han inscritos 24 000 participantes, o sea, x = 24000. Por eso, la cantidad de africanos es:

Afr = \frac{x}{60} = \frac{24000}{60} = 400

Para obtener más información sobre las proporciones, puedes visitar a brainly.com/question/24615636

8 0
2 years ago
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
1
Blababa [14]

Answer:

76

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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