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3 years ago

2 sine squared theta plus sine theta minus 1 equals 02sin2θ+sinθ−1=0

Mathematics

1 answer:

frutty [35]3 years ago

4 0

I did not even understand that equation

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A student broke this trapezoid into two triangles. She says she has enough information to find the area of it. Is she correct? E

forsale [732]

It depends on what measurements are given. Do you have a photo? Please revise your question

6 0

4 years ago

Read 2 more answers

Maddie buys stock that is worth $22 per share.On the first day,the value of the stock goes up 20%. On the second day,the value d

zepelin [54]

Answer:

At the end of the second day, the value of the share is $23.76

Step-by-step explanation:

Maddie bought $22 worth of share

20% increase of $22 share in the first day

= 20/100 × 22

= $4.40

The total value at the end of the $22 + $4.40

= $26.40

On the second day, 10% decrease of $26.40 is

= 10/100 × $26.4

= $2.64

At the end of the second date, the value of the share is $26.40 - $2.64

= $23.76

5 0

4 years ago

An object falls from a position of rest and

kumpel [21]

Answer:

About 4.1323 meters.

Step-by-step explanation:

We can use the following kinematic equations:

$\displaystyle v_f = v_0 + at \text{ and } \Delta d = v_0 t + \frac{1}{2} at^2$

We want to determine the distance the object has dropped after falling from rest and reaching an instantenous speed of 9 m/s.

We are given that the acceleration due to gravity is 9.8 m/s².

Using this fact and the first equation, find the time for which it took the object to reach 9 m/s. Note that the initial velocity is 0 m/s since the object started from rest.

$\displaystyle \begin{aligned} v_f = v_0 + at \\ \\ (9\text{ m/s}) & = (0\text{ m/s}) + (9.8\text{ m/s$^2$})t \\ \\ 9\text{ m/s} & = (9.8 \text{ m/s$^2$})t \\ \\ t &\approx0.9184 \text{ s} \end{aligned}$

To find how far the object dropped, we can use the second equation:

$\displaystyle\begin{aligned} \Delta d & = v_0 t + \frac{1}{2} at^2 \\ \\ & = (0\text{ m/s})(0.9184 \text{ s}) + \frac{1}{2}(9.8 \text{ m/s$^2$})(0.9184 \text{ s})^2 \\ \\ & = 4.1323 \text{ m} \end{aligned}$

In conclusion, the object would have dropped about 4.1323 meters.

6 0

3 years ago

Calculate the volume of the cylinder.<br> 4 cm<br> 10 cm<br> Use = 3.14.

Ymorist [56]

Volume is approximately 502.65 cm^2

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3 years ago

On what website Might one be able to find the most reliable information on eating disorders

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3 years ago