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3 years ago

Natalia bought 8 glitter wands for $50

Mathematics

2 answers:

vazorg [7]3 years ago

6 0

Answer:

4 wands for $20 does not have the same

6 wands for $37.50 has the same amount

10 wands for %65 does not

Step-by-step explanation:

i got it right

Sergio [31]3 years ago

4 0

Answer:

Each glitter wand costs $6.25

Step-by-step explanation:

Using the unit rate formula, in this scenario it would be $\frac{price}{item}$ , we can find the unit rate of the glitter wand.

$\frac{price}{item}=\frac{50}{8} = 6.25$

Hope this helps.

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A friend of mine is giving a dinner party. His current wine supply includes 9 bottles of zinfandel, 10 of merlot, and 12 of cabe

e-lub [12.9K]

Answer:

Step-by-step explanation:

From the given information:

The total number of wine = 9 + 10 + 12 = 31

(1)

The number of distinct sequences used for serving any five wines can be estimated by using the permutation of the number of total wines with the number of wines served.

i.e

= $^{31}P_5$

$=\dfrac{31!}{(31-5)!}$

$=\dfrac{31!}{(26)!}$

$=\dfrac{31\times 30\times 29\times 28\times 27\times 26!}{(26)!}$

= 20389320

(2)

If the first two wines served = zinfandel and the last three is either merlot or cabernet;

Then, the no of ways we can achieve this is:

= $^9P_2\times ^{22}P_3$

$= \dfrac{9!}{(9-2)!}\times \dfrac{22!}{(22-3)!}$

$= \dfrac{9!}{(7)!}\times \dfrac{22!}{(19)!}$

$= \dfrac{9*8*7!}{(7)!}\times \dfrac{22*21*20*19!}{(19)!}$

= 665280

(3)

The probability that no zinfandel is served is computed as follows:

Total wines (with zinfandel exclusion) = 31 - 9 = 22

Now;

the required probability is:

$= \dfrac{^{22}P_5 }{^{31}P_5}$

$= \dfrac{\dfrac{22!}{(22-5)!} } {\dfrac{31!}{(31-5)!} }$

$= \dfrac{\dfrac{22!}{17!} } {\dfrac{31!}{(26)! }}$

$= \dfrac{(\dfrac{22*21*20*19*18*17!}{17!})} {(\dfrac{31*30*29*28*27*26!}{(26)! })}$

= 0.1549

≅ 0.155

4 0

3 years ago

Which data would be best analyzed and communicated using a histogram?

Nady [450]

The data that would be best analyzed and communicated using a histogram is the average number of clams dredged up at different depth ranges (5–10 m, 10–15 m, etc.)
because when we are using x axix then we can use different range (5–10 m, 10–15m
so correct option is 4
hope it helps

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3 years ago

Daquavion ha some great video games.Nicholas has 3 more games than daquavion. If Nicholas has 14 games, how many does daqauvion

forsale [732]

If Nicholas has 14 games, Daqauvion has 11 games because 14-3=11

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3 years ago

HOW CAN WE SOLVE THIS 5-2+17=7 PLEASE HELP IAM CONFUSED 5X+17=7

Eva8 [605]

Answer:+ 3*1 = 2 + 3 = 5 3 + 7 =17 => 3 + 7*2 = 3 +14 = 17 4 + 5

Step-by-step explanation:

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