Hi there! :)
Find the perimeter by solving for y.
We know that a rectangle contains two pairs of parallel and congruent sides, therefore:
5y - 1 = 2y + 8
We can solve for y using this expression. Begin by subtracting 2y from both sides:
5y - 2y - 1 = 2y - 2y + 8
3y - 1 = 8
Add 1 to both sides:
3y - 1 + 1 = 8 + 1
3y = 9
Divide both sides by 3:
y = 3
Recall that the perimeter of a rectangle is:
P = 2l + 2w
Plug in the given expressions for the side lengths to find one equation:
P = 2(5y - 1) + 2(y - 1)
Simplify by distribution:
P = 10y - 2 + 2y - 2
Combine like terms:
P = 12y - 4
Plug in the solved value of y into this equation:
P = 12(3) - 4
P = 36 - 4
P = 32 cm.
Answer:
Just connect points Y and D with a straight line to make YD. Do the same for YE and YF, just attach Y to points E and F with a straight line.
If there are outliers, IQR is a better measure of the spread of data than range. The range will include the outliers, and make the data appear to have many more terms of a greater/lesser value than it has in reality. IQR shows the middle 50%, which (usually) doesn't contain outliers, so the majority of the data spread would be shown by IQR in a data sample with a significant amount of outliers. If your measure of the spread of data contains outliers, then the measure isn't accurate.
Answer:
x<-1
Step-by-step explanation:
2(x+6)<10
Distribute 2x+12<10
Subtract 12 2x<-2
Divide 2 x<-1
The correct question is
<span>Teresa graphs the following 3 equations: y=2x, y=x2+2, and y=2x2. She says that the graph of y=2x will eventually surpass both of the other graphs. Is Teresa correct? Why or why not?
we have that
y=2x
y=x</span>²+2
y=2x²
using a graph tool
see the attached figure
<span>We can affirm the following
</span>the three graphs present the same domain-----> the interval (-∞,∞)
The range of the graph y=2x is the interval (-∞,∞)
The range of the graphs y=x²+2 and y=2x² is the interval [0,∞)
therefore
<span>Teresa is not correct because the graph of y = 2x will not surpass the other two graphs since in the interval of [0, infinite) the three graphs present the same range</span>
