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3 years ago

A sale on polka dotted underwear you save 20% on the $50 worth you bought how much do you save

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

6 0

Answer:

is it 50 origanally or after the discount

Step-by-step explanation:

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witch expression can be used to convert 22 Australian dollars to US dollars. assume 1.2 Australian dollars equals one us dollar

Mumz [18]

Let x represent the number of US dollars required. From the information given,

1.2 Australian dollars equals one us dollar

Thus,

22 Australian dollars = x US dollars

We would have the following equations

1.2 = 1

22 = x

By crossmultiplying, we have

x * 1.2 = 1 * 22

1.2x = 22

Dividing both sides of the equation by 1.2, we have

1.2x/1.2x = 22/1.2

The expression that can be used to convert 22 Australian dollars to US dollars is

x = 22/1.2

7 0

1 year ago

PLEASE PLEASE HELP ME WITH THSI MATH PROBLEM!!!

S_A_V [24]

Answer:

Step-by-step explanation:

area of a trapezoid = 1/2 × (a + b) × h

so, we have

96 = 1/2 × ((4x - 1) + (x + 3)) × 6 = (5x + 2) × 3

32 = 5x + 2

30 = 5x

x = 6

a = 4x - 1 = 4×6 - 1 = 24 - 1 = 23

4 0

2 years ago

X - 12/2 = 20<br> hurry pls!!!

Westkost [7]

Answer:

Step-by-step explanation:

12/2=6

x-6=20

x-6+6=20+6

=26

7 0

3 years ago

Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = x2 sin(z)i + y2j + xyk, S is the part of the paraboloid z = 9 − x2 −

Korolek [52]

The vector field

$\vec F(x,y,z)=x^2\sin z\,\vec\imath+y^2\,\vec\jmath+xy\,\vec k$

has curl

$\nabla\times\vec F(x,y,z)=x\,\vec\imath+(x^2\cos z-y)\,\vec\jmath$

Parameterize $S$ by

$\vec s(u,v)=x(u,v)\,\vec\imath+y(u,v)\,\vec\jmath+z(u,v)\,\vec k$

where

$\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=(9-u^2)\end{cases}$

with $0\le u\le3$ and $0\le v\le2\pi$ .

Take the normal vector to $S$ to be

$\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k$

Then by Stokes' theorem we have

$\displaystyle\int_{\partial S}\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{2\pi}\int_0^3(\nabla\times\vec F)(\vec s(u,v))\cdot\left(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^3u^3(2u\cos^3v\sin(u^2-9)+\cos^3v\sin v+2u\sin^3v+\cos v\sin^3v)\,\mathrm du\,\mathrm dv$

which has a value of 0, since each component integral is 0:

$\displaystyle\int_0^{2\pi}\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin v\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\cos v\sin^3v\,\mathrm dv=0$

4 0

3 years ago

What is the area of a triangle with a base of 11 yards and a height of 13 yards?

laila [671]

Area of triangle = 1/2 x base x height

Given that base = 11 yards and height = 13 yards

Area of triangle = 1/2 x 11 x 13 = 71.5 yards²

Answer; 71.5 yd²

4 0

4 years ago

A sale on polka dotted underwear you save 20% on the $50 worth you bought how much do you save​

A sale on polka dotted underwear you save 20% on the $50 worth you bought how much do you save