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3 years ago

Please help Thanks!

Mathematics

1 answer:

8_murik_8 [283]3 years ago

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Papessa [141]

Answer:

d = 10/72

Step-by-step explanation:

c and d vary inversely

c = k/d

Where,

k = constant of proportionality

d = 2/9 when c = 5

c = k/d

5 = k ÷ 2/9

5 = k × 9/2

5 = 9k/2

Cross product

5*2 = 9k

10 = 9k

k = 10/9

c = k/d

c = 10/9 ÷ d

c = 10/9 × 1/d

c = 10/9d

find d when c = 8

c = 10/9d

8 = 10/9d

Cross product

8*9d = 10

72d = 10

d = 10/72

8 0

3 years ago

Find the nth term of a gp with (a. find term = 5, common ratio = 2

Rina8888 [55]

Step-by-step explanation:

we know,

$tn= a {(r)}^{n - 1} \\ T5 = a {(2)}^{5 - 1} \\ t5 = a \times {2}^{4} \\ = 16a$

Therefore, nth term of a given gp is

16a

7 0

3 years ago

What is the value of x? enter your answer in the box

antiseptic1488 [7]

Answer:

2(x+10) = 3x-30 (reason: vertical angles are congruent)

2x+20 = 3x-30

20 = 1x-30

1x = 20+30

1x = 50

x = 50

5 0

3 years ago

Read 2 more answers

2(15+3m)-7 Plz explain and answer

Alekssandra [29.7K]

6m+23

You have to use distributive property, so 15x2=30 and 2x3m= 6m. You then subtract 30 from 7 and get 23.

4 0

3 years ago

Read 2 more answers

Listed below are time intervals (min) between eruptions of a geyser. Assume that the "recent" times are within the past few y

Shalnov [3]

Answer:

p value = 0.039

t = - 2.169

Step-by-step explanation:

Applying the null and alternate hypothesis

$H_{0} : U1 = U2$

$H_{\alpha } : U1 \neq U2$

using excel worksheet to calculate for ( t and p )

t = -2.169

p = 0.039

from the results obtained

The conclusion is affected by the significance level because : 0.1 0.01

so when the significance level is = 0.1 the Null hypothesis is rejected and we can say the mean time interval will change while

if the significance level = 0.01 the Null hypothesis is accepted and we can not say the mean time interval has changed because the p -value is greater than 0.01

attached is the excel solution

7 0

3 years ago