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Leya [2.2K]
3 years ago
5

Please help Thanks!

Mathematics
1 answer:
8_murik_8 [283]3 years ago
7 0
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Elina [12.6K]

Hope you are doing well

Answer:

x=17

8 0
3 years ago
Phoebe, Andy and Polly share £270.
Stella [2.4K]
*Given
Money of Phoebe            - 3 times as much as Andy
Money of Andy                - 2 times as much as Polly
Total money of Phoebe,  - <span>£270
</span>    Andy and Polly

*Solution

Let
B - Phoebe's money
A - Andy's money
L - Polly's money

1. The money of the Phoebe, Andy, and Polly, when added together would total <span>£270. Thus, 
</span>
                  B + A + L  = <span>£270                     (EQUATION 1)

2. Phoebe has three times as much money as Andy and this is expressed as
  
                  B = 3A

3. Andy has twice as much money as Polly and this is expressed as

                  A = 2L</span>                           (EQUATION 2)
<span>
4. This means that Phoebe has ____ as much money as Polly, 

                 B = 3A
                 B = 3 x (2L)
                 B = 6L                            </span>(EQUATION 3)<span>

This step allows us to eliminate the variables B and A in EQUATION 1 by expressing the equation in terms of Polly's money only. 

5. Substituting B with 6L, and A with 2L, EQUATION 1 becomes, 

                  6L + 2L + L = </span><span>£270
</span>                                9L = <span>£270
</span>                                  L = <span>£30

So, Polly has </span><span>£30. 

6. Substituting L into EQUATIONS 2 and 3 would give us the values for Andy's money and Phoebe's money, respectively. 
</span>
                  A = 2L                           
                  A = 2(£30)
                  A = £60

Andy has £60

                  B = 6L                         
                  B = 6(£30)
                  B = £180

Phoebe has £180

Therefore, Polly's money is £30, Andy's is £60, and Phoebe's is £180.
7 0
3 years ago
John looked at his bank account and noticed that he had $2,029.90 in his account. All that he could remember is that he created
Over [174]

We will have that for the previous year, he had in the account:

m_{y6}=2029.90-\frac{2029.90\cdot6}{100}\Rightarrow m_{y6}=1908.106

For the year previous to that one, he had:

m_{y5}=1908.106-\frac{1908.106\cdot6}{100}\Rightarrow m_{y5}=1793.61964

For the previous year to that, he had:

m_{y4}=1793.61964-\frac{1793.61964\cdot6}{100}\Rightarrow m_{y4}=1686.002462

For the year previous to that one, he had:

m_{y3}=1686.002462-\frac{1686.002462\cdot6}{100}\Rightarrow m_{y3}=1584.842314

For the second year that the money was in the account, there was:

m_{y2}=1584.842314-\frac{1584.842314\cdot6}{100}\Rightarrow m_{y2}=1489.751775

And the orinial ammount of money that was in the account was:

m_{y1}=1489.751775-\frac{1489.751775\cdot6}{100}\Rightarrow m_{y1}=1400.366669

From this, we know that Jhon had originally $1400.37 in the bank account.

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1 year ago
I need help on this one
Ivan
All planes without a plane DIH.
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BGH; CDA; FID; FIH

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3 years ago
L^2+7L-30<br><br> I need the answer for hw
Romashka [77]

Answer:

(l-3)(l+10)

Step-by-step explanation:

7 0
1 year ago
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