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3 years ago

Square root 75 + square root 12

Mathematics

2 answers:

UNO [17]3 years ago

8 0

Well first we should simplify:
$\sqrt[5]{3}$ + $\sqrt[2]{3}$
This turns into:
$\sqrt[7]{3}$

Blizzard [7]3 years ago

5 0

$\sqrt{75}+\sqrt{12}=\sqrt{5^{2}\cdot 3}+\sqrt{2^{2}\cdot 3}\\\\=5\sqrt{3}+2\sqrt{3}\\\\=7\sqrt{3}$

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Read 2 more answers

Point P'P′P, prime is the image of P(6,0)P(6,0)P, left parenthesis, 6, comma, 0, right parenthesis under the translation (x,y)\t

gtnhenbr [62]

The location of point P is at (0, -1)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.

Translation is the movement of a point left, right, up or down in the coordinate plane.

We are given the coordinates of point P and asked to find the coordinates of the image P'.

Given point P at P(6, 0), A translation of (x,y)→(x−6,y−1) is done to produce an image P'. Therefore point P is translated 6 units left and 1 unit down to get P'.

Hence P' = (0, -1)

Therefore P' is at (0, -1)

Find more at: brainly.com/question/15639127

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