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DENIUS [597]
3 years ago
9

The average American spent $8,508 on health care in 2011. The cost of health care is projected to rise about 5.8% per year for t

he years 2012-2022. Calculate the projected amount the average American spent on health care in 2014
Mathematics
1 answer:
klio [65]3 years ago
4 0
<h3>The projected amount the average American spent on health care in 2014  is $ 10075.91</h3>

<em><u>Solution:</u></em>

Given that,

The average American spent $8,508 on health care in 2011

The cost of health care is projected to rise about 5.8% per year for the years 2012-2022

<em><u>The increasing function is given as:</u></em>

y = a(1+r)^t

Where,

y is future value

a is initial value

r is growth rate in decimal

t is number of years

From given,

a = 8508

r = 5.8 \% = \frac{5.8}{100} = 0.058

t = 2011 to 2014 = 3 years

<em><u>Substituting the values, we get,</u></em>

y = 8508(1 + 0.058)^3\\\\y = 8508(1.058)^3\\\\y = 8508 \times 1.1842\\\\y = 10075.914 \approx 10075.91

Thus the projected amount the average American spent on health care in 2014  is $ 10075.91

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Is it (sss) (side side side ) Hypotenuse-Leg (HL), ssa?(sas) aaa,asa,aas?
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  • Here, both the triangles have equal sides.
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<u>SSS,</u><u> </u><u>congruent.</u>

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2 years ago
If possible help me in this. I need to find the two odd numbers...​
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Part (a)

Consecutive odd integers are integers that odd and they follow one right after another. If x is odd, then x+2 is the next odd integer

For example, if x = 7, then x+2 = 9 is right after.

<h3>Answer:  x+2</h3>

========================================================

Part (b)

The consecutive odd integers we're dealing with are x and x+2.

Their squares are x^2 and (x+2)^2, and these squares add to 394.

<h3>Answer: x^2 + (x+2)^2 = 394</h3>

========================================================

Part (c)

We'll solve the equation we just set up.

x^2 + (x+2)^2 = 394

x^2 + x^2 + 4x + 4 = 394

2x^2+4x+4-394 = 0

2x^2+4x-390 = 0

2(x^2 + 2x - 195) = 0

x^2 + 2x - 195 = 0

You could factor this, but the quadratic formula avoids trial and error.

Use a = 1, b = 2, c = -195 in the quadratic formula.

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(2)\pm\sqrt{(2)^2-4(1)(-195)}}{2(1)}\\\\x = \frac{-2\pm\sqrt{784}}{2}\\\\x = \frac{-2\pm28}{2}\\\\x = \frac{-2+28}{2} \ \text{ or } \ x = \frac{-2-28}{2}\\\\x = \frac{26}{2} \ \text{ or } \ x = \frac{-30}{2}\\\\x = 13 \ \text{ or } \ x = -15\\\\

If x = 13, then x+2 = 13+2 = 15

Then note how x^2 + (x+2)^2 = 13^2 + 15^2 = 169 + 225 = 394

Or we could have x = -15 which leads to x+2 = -15+2 = -13

So, x^2 + (x+2)^2 = (-15)^2 + (-13)^2 = 225 + 169 = 394

We get the same thing either way.

<h3>Answer: Either 13, 15  or  -15, -13</h3>
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Step-by-step explanation:

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