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DENIUS [597]
4 years ago
9

The average American spent $8,508 on health care in 2011. The cost of health care is projected to rise about 5.8% per year for t

he years 2012-2022. Calculate the projected amount the average American spent on health care in 2014
Mathematics
1 answer:
klio [65]4 years ago
4 0
<h3>The projected amount the average American spent on health care in 2014  is $ 10075.91</h3>

<em><u>Solution:</u></em>

Given that,

The average American spent $8,508 on health care in 2011

The cost of health care is projected to rise about 5.8% per year for the years 2012-2022

<em><u>The increasing function is given as:</u></em>

y = a(1+r)^t

Where,

y is future value

a is initial value

r is growth rate in decimal

t is number of years

From given,

a = 8508

r = 5.8 \% = \frac{5.8}{100} = 0.058

t = 2011 to 2014 = 3 years

<em><u>Substituting the values, we get,</u></em>

y = 8508(1 + 0.058)^3\\\\y = 8508(1.058)^3\\\\y = 8508 \times 1.1842\\\\y = 10075.914 \approx 10075.91

Thus the projected amount the average American spent on health care in 2014  is $ 10075.91

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For which inequality would x = 8 not be a solution?4x + 3 &gt; 09x - 5 &lt; 100x + 4 ≤ 1072 ÷ x ≥ 4
galina1969 [7]

Given:

Given the inequalities:4

\begin{gathered} 4x+3>0 \\ 9x-5

Required: Identify the inequality in which x = 8 is a solution.

Explanation:

Substitute 8 for x in each inequality and check whether it satisfies the inequality.

Consider 4x + 3 > 0.

4\cdot8+3=35>0

So, x = 8 satisfies the inequality 4x + 3 > 0.

Consider 9x - 5 < 100.

9\cdot8-5=67

So, x = 8 satisfies the inequality 9x - 5 < 100.

Consider x + 4 ≤ 10.

8+4=12>10

So, x = 8 not satisfies the inequality.

Consider 72 ÷ x ≥ 4.

72\div8=9\ge4

So, x = 8 satisfies the inequality.

Final Answer: The inequality in which x = 8 is not a solution is x + 4 ≤ 10.

5 0
1 year ago
The cost of 4 cookies, 6 doughnuts, and 3 boxes of doughnut holes is $8.15. The cost of 2 cookies, 3 doughnuts, and 4 boxes of d
Naddika [18.5K]

Answer:

$1.25

Step-by-step explanation:

This can best be determined using a set of linear equations that are solved simultaneously.

This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

Let the cost of a cookie be c, cost of a doughnut be d and that of a box of doughnut hole be h then if cost of 4 cookies, 6 doughnuts, and 3 boxes of doughnut holes is $8.15, we have

4a + 6d + 3h = 8.15

and the cost of 2 cookies, 3 doughnuts, and 4 boxes of doughnuts holes is $7.20 then

2a + 3d + 4h = 7.20

Dividing the first by 2

2a + 3d + 1.5h = 4.075

subtracting from the second equation

2.5h = 3.125

h = 1.25

The cost of a box of doughnut holes is $1.25

5 0
3 years ago
Greg earned $45.76 in 6.4 hours. How much did he earn per hour?
Alisiya [41]

Answer:

The answer is $7.15 (A)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Represent each of these relations on {1, 2, 3, 4} with a matrix (with the elements of this set listed in increasing order). a) {
Irina-Kira [14]

Answer:

for a  a) {(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)}

\left[\begin{array}{cccc}0&1&1&1\\0&0&1&1\\0&0&0&1\\0&0&0&0\end{array}\right]

for b

b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}

\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]

for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}

\left[\begin{array}{cccc}0&1&1&1\\1&0&1&1\\1&1&0&1\\1&1&1&0\end{array}\right]

for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}

\left[\begin{array}{cccc}0&0&0&0\\0&0&0&1\\1&1&0&1\\0&0&0&0\end{array}\right]

Step-by-step explanation:

in matrix, arrays are placed in rows , which represents the horizontal sides from left to right, while arrays in the column are placed vertically from top to bottom. Here, we placed the arrays in a 4x4 matrix

for a  a) {(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)}

\left[\begin{array}{cccc}0&1&1&1\\0&0&1&1\\0&0&0&1\\0&0&0&0\end{array}\right]

for b

b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}

\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]

for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}

\left[\begin{array}{cccc}0&1&1&1\\1&0&1&1\\1&1&0&1\\1&1&1&0\end{array}\right]

for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}

\left[\begin{array}{cccc}0&0&0&0\\0&0&0&1\\1&1&0&1\\0&0&0&0\end{array}\right]

7 0
4 years ago
3. Which is a function?
OverLord2011 [107]

Answer:

C) {(12,3), (11,2), (10,1), (9,0), (8,1), (7,2), (6,3)} Is a function.

Step-by-step explanation:

The easiest way to tell if a Relation is a Function (in my opinion) is the Verticle Line test. Use your pairs and put them in a graph. Then connect the dots, and if your line at any point touches the graph once, then your Relation is a Function. If it touches the graph more than once, it is not a Function.

Regards!

4 0
3 years ago
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