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nikdorinn [45]
3 years ago
14

Quadrilateral T'R'A'M os rotated °S -goo about the origin.​

Mathematics
1 answer:
Anit [1.1K]3 years ago
7 0

Answer:

ang hirap naman plss answee

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Sensational Cell Phones offers a plan of $30 for the first 300 minutes, and an additional $0.30 for every minute over 300. Let t
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Answer:

Since g(f(x))=x g ( f ( x ) ) = x , f−1(x)=x2−1 f - 1 ( x ) = x 2 - 1 is the inverse of f(x)=2x+2 f ( x ) = 2 x + 2 .

5 0
3 years ago
Isabella has some dimes and some quarters. She has at most 25 coins worth a minimum of $4.45 combined. If Isabella has 17 dimes,
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A is 2

Step-by-step explanation:

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4 years ago
PLEASE HELP ME Determine whether the graph represents a proportional relationship. A graph is shown. The x-axis is labeled from
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Answer:

No, the graph does not represent a proportional relationship

Step-by-step explanation:

The equation that models a proportional relation is y=kx, where k is the constant of proportionality.

Based on your description, we have:

x          y

0          4

2          8

3          12

4          16

The graph of a proportional relation will always pass through the origin i.e the initial value is always zero.

The equation of this graph is not in the form y=kx.

Hence, the graph does not represent a proportional relationship because there is an initial value which is not zero.

6 0
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You are selling drinks at the carnival to raise money for your club. You sell lemonade for $2 per cup and orange drinks for $3 p
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If you need an equation the answer is 240= 2x + 3y
3 0
4 years ago
Help me with my work plz.
nordsb [41]

Answer:

(√366 - 3)/24

Step-by-step explanation:

Given the following:

cos∝ = √3/8 and sinβ = √3/3

Sin(∝-β) = sin∝cosβ - cos∝sinβ

Get sin∝

Since cos∝ = √3/8

adj = √3

hyp = 8

opp = √8² - (√3)²

opp = √64 - 3

opp = √61

Recall that sin∝ = opp/hyp  

sin∝ = √61/8

Get cosβ

Since sinβ =  √3/3

opp = √3

hyp = 3

adj =√3² - (√3)²

adj = √9-3

adj = √6

Recall that cosβ = adj/hyp

cosβ = √6/3

Substitute the gotten values into the formula

Sin(∝-β) = sin∝cosβ - cos∝sinβ

Sin(∝-β) = ( √61/8)(√6/3)- (√3/8)(√3/3)

Sin(∝-β) = √366/24 - √9/24

Sin(∝-β) = (√366 - 3)/24

6 0
3 years ago
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