Answer:
745 books are expected to be donated to the library at the end of Month 10
Step-by-step explanation:
There were 80 books donated at the library:
No=80
The number of books donated to a library is increasing by 25% each month:
There were 100 books donatd at the end of Month 1:
N1=100
N1=No+25%No
N1=No+(25/100)No
N1=No+0.25 No
N1=(1+0.25) No
N1=(1.25) No
(1) N1=(1.25)^1 No
N1=(1.25)^1 80
N1=(1.25) 80
N1=100
N2=N1+25%N1
N2=N1+(25/100)N1
N2=N1+0.25 N1
N2=(1+0.25) N1
N2=(1.25) N1
Replacing equation (1) in the equation above:
N2=(1.25) (1.25)^1 No
N2=(1.25)^(1+1) No
(2) N2=(1.25)^2 No
N3=N2+25%N2
N3=N2+(25/100)N2
N3=N2+0.25 N2
N3=(1+0.25) N2
N3=(1.25) N2
Replacing equation (2) in the equation above:
N3=(1.25) (1.25)^2 No
N3=(1.25)^(1+2) No
(3) N3=(1.25)^3 No
In general:
Nt=N(t)=(1.25)^t No
N(t)=(1.25)^t (80)
N(t)=80 (1.25)^t
where t is the number of the month
How many books are expected to be donated to the library at the end of Month 10?
t=10
N(10)=80 (1.25)^10
N(10)=80 (9.313225746)
N(10)=745.0580596
Rounding to the nearest whole number:
N(10)=745
Answer:
A. (0, 5)
Step-by-step explanation:
Physically speaking, the volume of the box and the side of the square cutout are positive value. So that the following inequations must be satisfied:
(1)
(2)
(3)
From (1), (2), (3) we find that:
(1):
(2):
(3):
We see that equation above is the multiplication of a first grade monomial and two first grade binomials, which means that:
In other words, the reasonable domain for this situation is A.
Answer:
(0, 1/3, 2/3, 1, 1 1/3, 1 2/3, 2)
Step-by-step explanation:
Given :. Length of row = yards
Spacing = 1/3 yard
Startibg point = 0
0 ;
0+1/3 = 1/3
1/3 + 1/3 = 2/3
2/3 + 1/3 = 2/3 = 1
1 + 1/3 = 1 1/3
1 1/3 + 1/3 = 1 2/3
1 2/3 + 1/3
(0, 1/3, 2/3, 1, 1 1/3, 1 2/3, 2)
Answer:
Step-by-step explanation:
To find the diagonal, use Pythagorean theorem,
diagonal² = side² + side²
= (9√3)² + (9√3)²
= 9²(√3)² + 9²(√3)²
= 81*3 + 81*3
= 243 + 243
= 486
diagonal = √486 = 22.05 units
