Question

WILL GIVE ABRAINLEST AND 50PTS

Answer 1

Answer:

a=-2 is extraneous solution.

Step-by-step explanation:

Given the equation

$\frac{3}{a+2}+\frac{2}{a}=\frac{4a-4}{a^2-4}$

we have to find the extraneous solution.

An extraneous solution is a solution to an equation, that emerges from the process of solving the problem but is not a valid solution to the problem.

$\frac{3}{a+2}+\frac{2}{a}=\frac{4a-4}{a^2-4}$

$\frac{3}{a+2}+\frac{2}{a}=\frac{4a-4}{a^2-4}\\\\\frac{3a+2(a+2)}{a(a+2)}=\frac{4(a-1)}{a^2-4}\\\\\frac{5a+5}{a(a+2)}=\frac{4(a-1)}{a^2-4}$

On solving, we get

The solution is a=4 and a=-2

Here the solution a=-2 is the valid solution as it makes the denominator 0.

⇒ a=-2 is extraneous solution.

Option 1 is correct.

Answer 2

The solution to your question is a=-2. Hope this helped you. I just took the test. So I know it is right. Can you please give me Brainliest?