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3 years ago

Count the total number of atoms in sio2:

1 answer:

8 0

Atoms are the basic units of matter and the defining structure of elements. We count the number of atoms by the total number of elements present in the compound. In this case, we have 1 atom of Si and 2 atoms of oxygen which would have 3 total number of atoms.

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If gas is initially at 350L and 500k then changes to 295K what is the new volume

Dimas [21]

<h2>Hello!</h2>

The answer is:

The new volume is equal to 206.5 L.

To solve this problem, we need to assume that the pressure is constant, and use the Charle's Law equation, so, solving we have:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

We are given:

$V_1=350L\\T_1=500K\\T_2=295K$

Then, using the Charle's Law equation, we have:

$\frac{350L}{500K}=\frac{V_2}{295K}$

$\frac{350L}{500K}=\frac{V_2}{295K}\\\\V_2=\frac{350L}{500K}*295K=206.5L$

Hence, we have that the new volume is equal to 206.5 L.

Have a nice day!

5 0

2 years ago

Urgent plzz help meeee thx

MakcuM [25]

Answer:

Explanation:

From the question given above, the following data were obtained:

t–butyl ion = (CH₃)₃C⁺

Number of valence electron =?

The valence electron(s) talks about the combining power of an element or compound as the case may be.

Considering the t–butyl ion, (CH₃)₃C⁺ we can see that it has a charge of +1 indicating that it has given out 1 electron to attain the stable octet configuration which has a valence electrons of 8. Thus, the valence electron of t–butyl ion, (CH₃)₃C⁺ is 8

5 0

2 years ago

How reactive is an atom of Sodium(Na) and why?

s344n2d4d5 [400]

3rd one:
it is very reactive because it does not have a full Valence shell.

this is because it's in group 1 so it has one electron in its outer shell, and it wants to have a full outer shell ( which it can gain by losing the electron in a reaction).

Hope this helps :)

5 0

2 years ago

Please help, I really don’t understand this!!!

kap26 [50]

<u>Analysing the Question:</u>

We are given the balanced equation:

C₆H₁₂O₆ + 6O₂→ 6CO₂ + 6H₂O

from this equation, we can say that: <em>for every 1 mole of Glucose, we need 6 moles of Oxygen</em>

<u>Moles of Glucose used in the reaction:</u>

Molar mass of Glucose = 180 grams / mol

Given mass of Glucose = 1 gram

Mole of Glucose = Given mass / Molar mass

Moles of Glucose = 1 / 180 moles

<u>Mass of Oxygen required:</u>

We know that for every mole of Glucose, we need 6 moles of Oxygen

So, for 1/180 moles of Glucose, we need 6 / 180 = 1 / 30 moles of Oxygen

Mass of 1 / 30 moles of Oxygen:

Mass = Molar mass * number of moles

Mass of Oxygen = 32 * 1/30

Mass of Oxygen = 32 / 30

Mass of Oxygen = 1.06 grams

5 0

3 years ago

Which metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe? auau cucu mnmn agag

Cerrena [4.2K]

Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.

Commonly, sacrificial electrodes are employed to stop another metal from corroding or oxidising. A metal that is more reactive than the metal being shielded must serve as the sacrificial electrode. Magnesium, aluminium, and zinc are the three metals most frequently used in sacrificial anodes.

Manganese-Magnesium (Mn-Mg) electrode is more suited for on-shore pipelines where the electrolyte (soil or water) resistivity is higher since it has the highest negative electropotential of the three. In order to replenish any electrons that could have been lost during the oxidation of the shielded metal, the highly active metal offers its electrons.

Therefore, Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.

Learn more about electrode here:

brainly.com/question/17060277

#SPJ4

3 0

1 year ago