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3 years ago

10

Count the total number of atoms in sio2:

1 answer:

grigory [225]3 years ago

8 0

Atoms are the basic units of matter and the defining structure of elements. We count the number of atoms by the total number of elements present in the compound. In this case, we have 1 atom of Si and 2 atoms of oxygen which would have 3 total number of atoms.

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maria [59]

Answer:

Na and Cl

Explanation:

An ionic compound is solid at state room temperature. Therefore Na and Cl would be the correct answer :)

5 0

2 years ago

What is the gram-formula mass of Fe(NO3)3?

dusya [7]

M Fe = 55,85g ≈ 56g
m O = 16g
m N = 14g
m Fe(NO3)3 = 56g + 3*14g + 3*3*16g = 242g/mol

answer: (4)

8 0

3 years ago

Read 2 more answers

Franklin used X-ray crystallography to determine that the shape of the dna molecule is what

Ivanshal [37]

Answer:

cgjffhj

8#8#**$*$&$&$,jdjbd

5 0

2 years ago

In part 3 of the lab, you discovered the relationship between temperature (T) and volume (V) of a gas.

rewona [7]

$\frac{V1}{T1}$ = k

<u>Explanation:</u>

The relation between volume, V of gas and Temperature, T of a gas is related by Charles Law.

This law states that the volume of a given amount of gas held at a constant pressure is directly proportional to the Kelvin temperature

Thus,

$\frac{V}{T}$ = k

where k is a constant

Therefore,

$\frac{V1}{T1}$ = $\frac{V2}{T2\\}$ = $\frac{V3}{T3}$ ...

This shows, as the volume of a gas goes up, the temperature also goes up and vice-versa.

7 0

3 years ago

Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el

Likurg_2 [28]

Answer: 281 hours

Explanation:-

1 electron carry charge= $1.6\times 10^{-19}C$

1 mole of electrons contain= $6.023\times 10^{23}$ electrons

Thus 1 mole of electrons carry charge= $\frac{1.6\times 10^{-19}}{1}\times 6.023\times 10^{23}=96500C$

$Cu^{2+}+2e^-\rightarrow Cu$

$96500\times 2=193000Coloumb$ of electricity deposits 1 mole or 63.5 g of copper

0.0635 kg of copper is deposited by 193000 Coloumb

11.5 kg of copper is deposited by= $\frac{193000}{0.0635}\times 11.5=34952756$ Coloumb

$Q=I\times t$

where Q= quantity of electricity in coloumbs = 34952756 C

I = current in amperes = 34.5 A

t= time in seconds = ?

$34952756 C=34.5A\times t$

$t=1013123sec=281hours$

Thus it will take 281 hours to plate 11.5 kg of copper onto the cathode if the current passed through the cell is held constant at 34.5 A.

8 0

3 years ago