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Schach [20]
4 years ago
14

Find u · v. u = 6i − 5j v = i − j

Mathematics
1 answer:
Mekhanik [1.2K]4 years ago
6 0

Answer:

i am not intelligent boy I am slow in math

Step-by-step explanation:

ok please let me know

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Jennifer has 12 pineapples in her lunchbox. For every pineapple she has 6 strawberries. How many pieces of fruit does Jennifer h
satela [25.4K]

Answer:

84 pieces of fruit.

Step-by-step explanation:

I got this answer by doing 12*6 = 72, but this is not our final answer because we still have to add the pineapples which gives us 84.

Hope this helps!!

5 0
3 years ago
Read 2 more answers
Among the contestants in a competition are 46 women and 23 men. If 5 winners are randomly selected, what is the probability that
eimsori [14]

Answer:

When 5 winners are randomly selected, the probability that they are all men is 0.003.

Step-by-step explanation:

Among the contestants in a competition are 46 women and 23 men.

Total persons are =46+23=69

When one winner is chosen, there are 68 people left, when second winner is chosen there are 67 people left and so on.

So, the probability that they are all men is given by:

\frac{23}{69} \times\frac{22}{68} \times\frac{21}{67} \times\frac{20}{66} \times\frac{19}{65}

= \frac{4037880}{1348621560} = 0.002999 ≈ 0.003

Therefore, when 5 winners are randomly selected, the probability that they are all men is 0.003.

7 0
3 years ago
If your speed limit was 70 miles a an hour how long will it take you to travel 140 miles with no traffic
Tpy6a [65]

It will take you 2 hours since ur going 70 mph divide the 140 mph by 70mph . Hope this helps :)

6 0
3 years ago
"write an equation of the perpendicular bisector or the segment with endpoints Q(-2,0) and R(6,12). what does y equal? ​
anygoal [31]

Answer:

The equation of perpendicular bisector of QR is:

y = -\frac{2}{3}x+\frac{22}{3}y=−32x+322

Step-by-step explanation:

Given points are:

Q(-2,0)\ and\ R(6,12)Q(−2,0) and R(6,12)

First of all, we have to find the slope of the given line

So,

m = \frac{y_2-y_1}{x_2-x_1}m=x2−x1y2−y1

Here

(x1,y1) = (-2,0)

(x2,y2) = (6,12)

Let m1 be the slope of QR:

Then

\begin{gathered}m_1 = \frac{12-0}{6+2}\\= \frac{12}{8}\\= \frac{3}{2}\end{gathered}m1=6+212−0=812=23

Let m2 be the slope of perpendicular bisector

We know that the product of slopes of two perpendicular lines is -1

\begin{gathered}m_1.m_2 = -1\\\frac{3}{2}.m_2 = -1\\m_2 = -1 * \frac{2}{3}\\m_2 = -\frac{2}{3}\end{gathered}m1.m2=−123.m2=−1m2=−1∗32m2=−32

The bisector will pass through the mid-point of QR

\begin{gathered}M = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\M = (\frac{-2+6}{2}, \frac{0+12}{2})\\M = (\frac{4}{2}, \frac{12}{2})\\M = (2,6)\end{gathered}M=(2x1+x2,2y1+y2)M=(2−2+6,20+12)M=(24,212)M=(2,6)

Slope-intercept form of equation is:

y = m_2x+by=m2x+b

Putting the value of slope

y = -\frac{2}{3}x+by=−32x+b

Putting (2,6) in the equation

\begin{gathered}6 = -\frac{2}{3}(2)+b\\6 = -\frac{4}{3}+b\\b = 6+\frac{4}{3}\\b = \frac{18+4}{3}\\b = \frac{22}{3}\end{gathered}6=−32(2)+b6=−34+bb=6+34b=318+4b=322

So,

y = -\frac{2}{3}x+\frac{22}{3}y=−32x+322

Hence,

The equation of perpendicular bisector of QR is:

y = -\frac{2}{3}x+\frac{22}{3}y=−32x+322

4 0
3 years ago
According to a survey by the Administrative Management Society, one-half of U.S. companies give employees 4 weeks of vacation af
andreyandreev [35.5K]

Answer:

a

P(2\leq X\leq 5)=0.875

b

P(X

Step-by-step explanation:

Let the random X variable representing the 6 companies that give 4 weeks of vacation after 15 years of employment:

-let p=0.5 be the probability of vacation. Since the companies are independent, X assumes a binomial random variable:P(X=x)=b(x;6,0.5)\\\\={6 \choose x}(0.5)^x(0.5)^{6-x}\\\\={6 \choose x}(0.5)^6, \ x=0,1,2,3...\ \ \ eqtn1

#Probability that the number of companies that give vacation is anywhere from 2 to 5:

We use equation 1;

P(2\leq X\leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\={6 \choose 2}(0.5)^6+{6 \choose 3}(0.5)^6{6 \choose 4}(0.5)^6+{6 \choose 5}(0.5)^6\\\\=0.0156(15+20+15+6)\\\\=0.875

Hence the probability that between 2 and 5 companies give vacation is 0.875

b. The probability that fewer than 3 companies give vacation is calculated as:

From equation one we get:

P(X

Hence the probability that less than three companies give vacation is 0.3432

3 0
3 years ago
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