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marta [7]
2 years ago
11

Mrs. Davis' gym class has 24 girls and 18 boys. She wants to separate the class into stations Each station must have the same nu

mbers of girls and boys.
What is the greatest number of stations Mrs. Davis can make it every student has to participate in a station?

A.2 stations

B.3 stations

C.6 stations

D.7 stations​
Mathematics
1 answer:
Nana76 [90]2 years ago
3 0

Answer:

6 stations

Step-by-step explanation:

24=1,2,3,4,6,8,12,24

18=1,2,3,6,9,18

Now we have to find which numbers are the same but that are the largest.

so It would be 6.

So Mrs.Davis can have every student participate in 6 stations.

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Morty buys and sells computer parts
mart [117]

Answer:

  • <em>1. Morty's total cost for the items he purchased was </em><u><em>$210</em></u>
  • <em>2. Morty's revenue from the sale of the items was </em><u><em>$547</em></u>
  • <em>3. Morty's Total profit was </em><u><em>$337</em></u>

<em />

Explanation:

The complete question is:

<em>Morty buys and sells computer parts. He bought two monitors for $25 each and later sold them for $88 each. He bought four cases for $15 each and later sold them for $24 each. He bought five memory modules for $20 each and later sold them for $55 each.</em>

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  • <em>Morty's total cost for the items he purchased was</em>
  • <em>Morty's revenue from the sale of the items was</em>
  • <em>Morty's Total profit was </em>

<em />

<h2><em>Solution</em></h2>

<em />

<u><em>1. Morty's total cost for the items he purchased was</em></u>

<em />

Build a table with the number of parts and their costs:

Component         Amout    Unit cost  Total cost

                                               $                 $

Monitors                2             25                50

Cases                     4             15                 60

Memory                  5             20               100

Total cost = $50 + $60 + $100 = $210

<u><em>2. Morty's revenue from the sale of the items was</em></u>

<em />

Build a table with the number of parts and their selling prices:

Component         Amout    Unit price  Total cost

                                               $                 $

Monitors                2              88               176

Cases                     4              24                96

Memory                  5             55              275

Total revenue: $176 + $96 + $275 = $547

<u><em>3. Morty's Total profit was </em></u>

<em />

The total profit is the total revenue less the total cost: $547 - $210 = $337.

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Answer:

\lim _{x\to 2}\:\frac{x-2}{x^2-2}\\\\  \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}\\\\ \lim _{x\to \frac{5}{2}}\left\frac{2x^2+x-15}{2x-5}\right

Step-by-step explanation:

a) \lim _{x\to 3}\:\frac{x^2-10x+21}{x^2+4x-21}=\lim \:_{x\to \:3}\:\frac{\left(x-7\right)\left(x-3\right)}{\left(x+7\right)\left(x-3\right)}=\lim \:_{x\to \:3}\:\frac{x-7}{x+7}=\frac{3-7}{3+7}=-\frac{4}{10}=-\frac{2}{5}

b) \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=\lim \:_{x\to -\frac{3}{2}}\:\frac{\left(2x+3\right)\left(x-4\right)}{\left(2x+3\right)}=\lim \:\:_{x\to \:-\frac{3}{2}}\:\left(x-4\right)=-\frac{3}{2}-4\\ \\ \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=-\frac{11}{2}

c) \lim _{x\to 2}\:\frac{x-2}{x^2-2}=\frac{2-2}{\left(2\right)^2-2}=\frac{0}{4-2}=0

d) \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}=\lim _{x\to 11}\:\frac{\left(x-11\right)\left(x+17\right)}{\left(x-11\right)\left(x+14\right)}=\lim _{x\to 11}\:\frac{\left(x+17\right)}{\left(x+14\right)}=\frac{11+17}{11+14}=\frac{28}{25}

e) \lim _{x\to 3}\:\frac{x^2-8x+15}{x-3}=\lim \:_{x\to \:3}\:\frac{\left(x-3\right)\left(x-5\right)}{x-3}=\lim _{x\to 3}\left(x-5\right)=3-5=-2

f) \lim _{x\to \frac{5}{2}}\left(\frac{2x^2+x-15}{2x-5}\right)=\lim \:_{x\to \:\frac{5}{2}}\frac{\left(2x-5\right)\left(x+3\right)}{2x-5}=\lim \:\:_{x\to \:\:\frac{5}{2}}\left(x+3\right)=\frac{5}{2}+3=\frac{11}{2}

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3 years ago
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