Can someone help me solve for x+y=3 and x-y=1?

1 answer:

8 0

$\underline{+\left\{\begin{array}{ccc}x+y=3\\x-y=1\end{array}\right}\ \ \ \ |\text{add both sides of the equations}\\\\.\ \ \ \ 2x=4\ \ \ \ |:2\\.\ \ \ \ x=2\\\\\text{put the value of x to the first equation}\\\\2+y=3\ \ \ \ |-2\\\\y=1\\\\Answer:\ x=2,\ y=1\to(2,\ 1)$

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3 years ago

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3 years ago

Read 2 more answers

In isosceles triangle ABC, AC=BC=20, the measure of angle A=68, and CD is the altitude to side AB. What is CD to the nearest 10t

antiseptic1488 [7]

Answer:

Step-by-step explanation:

Comment

The way the diagram looks when it is drawn is that you are going to need the sine function to solve for the side opposite which is CD.

Formula

Sin(A) = Sin(68 = opposite / hypotenuse Substitute values.

Solution

sin(68) = altitude (side opposite) / 20 multiply both sides by 20

20*sin(68) = 20* altitude / 20 substitute for sin(68)

20* 0.9272 = altitude

altitude = 18.5

Answer: 18.5 to the nearest tenth

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2 years ago

3 1/9+2 1/4= what is the answer

34kurt

Answer:
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Step-by-step explanation:

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