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Phoenix [80]
3 years ago
15

I would like to get some information of how to do this...​

Mathematics
1 answer:
Inessa05 [86]3 years ago
3 0

Answer:

The area is approximately 30.69 cm^2.

Step-by-step explanation:

To solve this problem, we first have to recognize that the side of the block is a rectangle with a semicircle missing.  This means that to find the area, we must find the area of the rectangle and then subtract the area of the semicircle.  Using the respective formulas, we get the following expression for area:

A = (length * width) - (1/2*pi*r^2)

Now, we must plug in the given values shown in the figure.  The length is 9 cm, the width is 4.5 cm, and the diameter is 5 cm.  However, the formula asks for the radius, which is simply half of the diameter, or 2.5 cm.  

A = (9 cm * 4.5 cm) - (1/2 * 3.14 * (2.5 cm)^2)

Next, we should perform the operations indicated inside the parentheses.

A = 40.5 cm^2 - 9.81 cm^2

Finally, we can subtract the two values (this represents taking away the area of the semicircle from the rectangle).

A = 30.69 cm^2

Therefore, the area of the side is approximately 30.69 cm^2.

Hope this helps!

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Answer:

C

Step-by-step explanation:

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7+3x=3x+8

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So the final statement for the solution would be

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lozanna [386]

Answer

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Step-by-step explanation:

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6 0
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Any help would be appreciated. Thank you!
trapecia [35]

Answer:

Area =62.5\sqrt{6} square units

AB=5\sqrt{15} units

BC=5\sqrt{10} units

Step-by-step explanation:

In a right triangle the altitude drawn to the hypotenuse is the geometric mean of the segments at which this altitude divides the hypotenuse.

So,

BD^2=15\cdot 10\\ \\BD^2=150\\ \\BD=\sqrt{150}=5\sqrt{6}\ units

a. The area of the triangle ABC is

A_{ABC}=\dfrac{1}{2}\cdot BD\cdot AC=\dfrac{1}{2}\cdot 5\sqrt{6}\cdot (15+10)=\dfrac{125\sqrt{6}}{2}=62.5\sqrt{6}\ un^2.

b. The legs of the right triangle are geometric means of the segment adjacent to this leg and the hypotenuse, so

AB^2=AD\cdot AC=15\cdot 25\Rightarrow AB=5\sqrt{15}\ units\\ \\BC^2=CD\cdot AC=10\cdot 25\Rightarrow BC=5\sqrt{10}\ units

5 0
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two patterns start at 0. the rule for pattern A is add 2. the rule for pattern B is add 3. what is the value of pattern B when p
mariarad [96]

Answer:4.5

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A   0   1       2      3

B   0   1.5    3     4.5

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