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Phoenix [80]
3 years ago
15

I would like to get some information of how to do this...​

Mathematics
1 answer:
Inessa05 [86]3 years ago
3 0

Answer:

The area is approximately 30.69 cm^2.

Step-by-step explanation:

To solve this problem, we first have to recognize that the side of the block is a rectangle with a semicircle missing.  This means that to find the area, we must find the area of the rectangle and then subtract the area of the semicircle.  Using the respective formulas, we get the following expression for area:

A = (length * width) - (1/2*pi*r^2)

Now, we must plug in the given values shown in the figure.  The length is 9 cm, the width is 4.5 cm, and the diameter is 5 cm.  However, the formula asks for the radius, which is simply half of the diameter, or 2.5 cm.  

A = (9 cm * 4.5 cm) - (1/2 * 3.14 * (2.5 cm)^2)

Next, we should perform the operations indicated inside the parentheses.

A = 40.5 cm^2 - 9.81 cm^2

Finally, we can subtract the two values (this represents taking away the area of the semicircle from the rectangle).

A = 30.69 cm^2

Therefore, the area of the side is approximately 30.69 cm^2.

Hope this helps!

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Find the optimal solution for the following problem. (Round your answers to 3 decimal places.)
irina1246 [14]

Answer:

Maximize C =9x + 7y

8x + 10y \leq 17

11x + 12y\leq 25

and x ≥ 0, y ≥ 0

Plot the lines on graph

8x + 10y \leq 17

11x + 12y\leq 25

x\geq 0

y\geq 0

So, boundary points of feasible region are (0,1.7) , (2.125,0) and (0,0)

Substitute the points in  Maximize C

At  (0,1.7)

Maximize C =9(0) + 7(1.7)

Maximize C =11.9

At  (2.125,0)

Maximize C =9(2.125) + 7(0)

Maximize C =19.125

At   (0,0)

Maximize C =9(0) + 7(0)

Maximize C =0

So, Maximum value is attained at   (2.125,0)

So, the optimal value of x is 2.125

The optimal value of y is 0

The maximum value of the objective function is 19.125

4 0
3 years ago
You need to be at least 39.37 inches tall (about a meter) to ride on a bumper car. Diego’s cousin is 35.75 inches tall. How many
blsea [12.9K]
39.37-35.75=3.62

3.62 inches
6 0
2 years ago
Rene made a 90 % on her math test. If she answered 20 problems correctly , how many problems were on the test ?
MakcuM [25]

Answer:

Rene made = 90 on her math test

If she answer =20problems correctly

we know,

how many problem were there = ?

there where = 90-20

= 70

There where 70 problems

8 0
2 years ago
ITS TIMED PLEASE HELP​
Lubov Fominskaja [6]

Answer:

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

f(x)=\frac{1}{2}x^{2}-4x+5

Convert to vertex form

f(x)-5=\frac{1}{2}x^{2}-4x

Factor the leading coefficient

f(x)-5=\frac{1}{2}(x^{2}-8x)

f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x-4)^{2}

f(x)=\frac{1}{2}(x-4)^{2}-3

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

5 0
3 years ago
Which expression is equivalent to 6x - 24?
hodyreva [135]
The correct answer is C. 6(x-4)
6 0
2 years ago
Read 2 more answers
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