Let's say that FH and EG intersection is O,
So we have the following:
OF = 2
OH = 5
Just because F and H are midpoints it means that EO = OG = x
And as it's given the area S=35
On the other hand
S = OF*OG/2 + OG*OH/2 + OH*OE/2 + OE*OF/2 = 2*x/2 + x*5/2 + 5*x/2 + x*2/2 = 2*x + 5*x = 7*x = 35
7x = 35 so x = 35/7 = 5
Answer: 5 units
Option 3, is correct.
Just find the one that have the x's only, not the one that is squared or without one. It doesn't matter if the term is a negative or positive.
If you have any further questions, please reach out to me :)
Answer:
∡TQS = 10x -3
Step-by-step explanation:
∡TQS = ∡RQS - ∡RQT
= 22x - 11 - (12x - 8)
= 10x -3
Answer:
(-9,-7)
Step-by-step explanation:
(x,y)—>(-x,-y)
(9,7)—>(-(9),-(7))=(-9,-7)
