If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)
Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm
The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.
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In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
<h3>
Answer: Parallelogram</h3>
You could use the parallelogram rule to add the vectors, or you could use the tip-to-tail method (your textbook might call it the "head to tail method" but it's the same idea).
An example of the parallelogram method is shown below with adding the vector u = (-4,4) in red to the vector v = (8,2) in blue to get the vector w = (4,6) in green. The green resultant vector is one of the diagonals of the parallelogram
Side note: The other diagonal is either u-v or v-u depending on your reference point.
Angles in a line = 180
180-165 = 15 degrees
15 + 45 + ? = 180
60 + ? = 180
? = 120
Answer:
No.
Step-by-step explanation:
Well, is the points (1, -9) does satisfy the equation y = 3x - 6. Then, substituting the values of x, and, y, into the equation y = 3x - 6, we should get a true equation.
y = 3x - 6
-9 = 3 * 1 - 6
-9 = 3 - 6
-9 = -3.
So, the points (1, -9) does not satisfy the equation y = 3x - 6.
Answer:
f(x) = 54(two-thirds) Superscript x minus 1
Step-by-step explanation:
Given that:
First peak : 36 / 54=2/3
Second peak : 24 / 36 = 2/3
The common ratio here is 2/3 ; which mean each bounce height is 2/3 of previous height
Modeling this using geometric progression :
An=a1r^(n-1)
An = nth term of a geometric progression
a1=first term
r=common ratio = 2/3
n = nth term
a1=54
Substituting into the above formular :
An=54(2/3)^(n-1)
