Answer:
exact area = 25(pi) m^2
approximate area = 78.54 m^2
Step-by-step explanation:
diameter = 10 m
radius = diameter/2 = 10 m / 2 = 5 m
area = (pi)r^2
area = (pi)(5 m)^2
area = 25(pi) m^2
area = 78.54 m^2
In a quadratic equation
q(x) = ax^2 + bx + c
The discriminant is = b^2 - 4ac
We have that discriminant = 3
If
b^2 - 4ac > 0, then the roots are real.
If
b^2 - 4ac < 0 then the roots are imaginary
<span>In
this problem b^2 - 4ac > 0 3 > 0 </span>
then
the two roots must be real
Answer:
a(6) = 37.97
Step-by-step explanation:
If the first term a(1) is 5 and the common ratio r is 3/2, then the general formula for this geometric sequence is
a(n) = 5*r^(n - 1).
Thus, the 6th term is a(6) = 5*(3/2)^(6 - 1), or a(6) = 5(3/2)^5 = 37.97
