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3 years ago

A rectangular retaining wall has an area of

Mathematics

1 answer:

Veronika [31]3 years ago

8 0

Answer:

The height of wall is 3 feet and length of wall is 5 feet

Step-by-step explanation:

Given as :

The Area of retaining wall = 15 square feet

Let The width of wall = W feet

The Height of wall = ( W - 2 ) feet

Now, Area of Rectangle = Height width

Or , 15 ft² = ( W - 2 ) ft × W ft

Or, 15 = W² - 2 W

Or, W² - 2 W - 15 = 0

Or, W² - 5 W + 3 W - 15 = 0

Or, W ( W - 5 ) + 3 ( W - 5 ) = 0

So , ( W - 5 ) ( W + 3 ) = 0

So, W = 5 , - 3

∴ The width of wall = W = 5 feet

And The Height of wall = ( W - 2 ) = 5 - 2 = 3 feet

Hence The height of wall is 3 feet and length of wall is 5 feet. Answer

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3 years ago

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3 years ago

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3 years ago

Write an inequality for x that would give this rectangle a perimeter of at least 300ft

Travka [436]

Answer:

The inequality for $x$ is:

$x\geq 142$

Step-by-step explanation:

Given:

Width of rectangle = 3 ft

Height or length of rectangle = $(x+5)$ ft

Perimeter is at least 300 ft

To write an inequality for $x$ .

Solution:

Perimeter of a rectangle is given as:

⇒ $2l+2w$

where $l$ represents length of the rectangle and $w$ represents the width of the rectangle.

Plugging in the given values in the formula, the perimeter can be given as:

⇒ $2(x+5)+2(3)$

Using distribution:

⇒ $2x+10+6$

Simplifying.

⇒ $2x+16$

The perimeter is at lest 300 ft. So, the inequality can be given as:

⇒ $2x+16\geq 300$

Solving for $x$

Subtracting both sides by 16.

⇒ $2x+16-16\geq 300-16$

⇒ $2x\geq284$

Dividing both sides by 2.

⇒ $\frac{2x}{2}\geq \frac{284}{2}$

⇒ $x\geq 142$ (Answer)

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3 years ago

a group of 31 friends gets together to play a sport. first people must be divided into teams. each team has to exactly 4 players

azamat

We have the following values:
Total people: 31
People per team: 4
The number of teams will then be:
N = (31) / (4)
N = 7.75
Round to the previous whole number.
N = 7
There are 7 teams.
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3 years ago