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Komok [63]
3 years ago
14

A rectangular retaining wall has an area of

Mathematics
1 answer:
Veronika [31]3 years ago
8 0

Answer:

The height of wall is 3 feet and length of wall is 5 feet

Step-by-step explanation:

Given as :

The Area of retaining wall = 15 square feet

Let The width of wall = W feet

The Height of wall = ( W - 2 ) feet

Now, Area of Rectangle = Height  width

Or , 15 ft² = ( W - 2 ) ft × W ft

Or,  15 = W² - 2 W

Or,   W² - 2 W - 15 = 0

Or,  W² - 5 W + 3 W - 15 = 0

Or, W ( W - 5 ) + 3 ( W - 5 ) = 0

So , ( W - 5 ) ( W + 3 ) = 0

So, W = 5 , - 3

∴ The width of wall = W = 5 feet

And The Height of wall = ( W - 2 ) = 5 - 2 = 3  feet

Hence The height of wall is 3 feet and length of wall is 5 feet. Answer

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3 years ago
Write an inequality for x that would give this rectangle a perimeter of at least 300ft
Travka [436]

Answer:

The inequality for x is:

x\geq 142

Step-by-step explanation:

Given:

Width of rectangle = 3 ft

Height or length of rectangle = (x+5) ft

Perimeter is at least 300 ft

To write an inequality for x.

Solution:

Perimeter of a rectangle is given as:

⇒ 2l+2w

where l represents length of the rectangle and w represents the width of the rectangle.

Plugging in the given values in the formula, the perimeter can be given as:

⇒ 2(x+5)+2(3)

Using distribution:

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Simplifying.

⇒ 2x+16

The perimeter is at lest 300 ft. So, the inequality can be given as:

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Solving for x

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⇒ 2x+16-16\geq 300-16

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Dividing both sides by 2.

⇒ \frac{2x}{2}\geq \frac{284}{2}

⇒ x\geq 142   (Answer)

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3 years ago
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azamat
We have the following values:
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they can make about 7 teams.
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