Find the third iterate, x3, of the function f(x) = 3x + 5 for an initial value of x0 = 1.

1 answer:

4 0

Find the third iterate, x3, of the function f(x) = 3x + 5 for an initial value of x0 = 1. x1 = 3(1) + 5 = 8 ... x2 = 3(8) + 5 = 29 ... x3 = 3(29) + 5 = 92

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