Answer:
it should be 490 joules
Step-by-step explanation:
9.8m/s^2
10kg * 9.8 * 3m
10kg*9.8*5m
<u>Answer:</u>
Given below.
<u>Explanation:</u>
Coordinates given: W( -4, -3 ) , X( 1 , -2 ), Y(2, -7 ) , Z( -3, -8)
To find the distance we will use the formula: distance=√((x2-x1)²+(y2-y1)²)
WX = √((1--4)²+(-2--3)²)
= √26
YZ = √((-3-2)²+(-8--7)²)
= √26
XY = √((2-1)²+(-7--2)²)
= √26
WZ = √(-3--4)²+(-8--3)²
= √26
WY = √(2--4)²+(-7--3)²
= 2√13
XZ = √(-3-1)²+(-8--2)²
= 2√13
Answer:
<h3><u>x=4</u> is the right answer.</h3>
Answer:
0.128rad/sec
Step-by-step explanation:
Let x represent the between the man and the point on the path
θ = the angle
dx/dt = 4 ft/s
dθ/dt = rate is the searchlight rotating when the man is 15 ft from the point on the path closest to the searchlight
tan θ = x/20 ft
Cross Multiply
20tan θ = x
dx/dt = 20sec² θ dθ/dt
dθ/dt = 1/20 × cos² θ dx/dt
dθ/dt= 1/20 × cos² θ × 4
dθ/dt = 1/5 × cos² θ
Note : cos θ = 4/5
dθ/dt = 1/5 × (4/5)²
dθ/dt = 16/125
dθ/dt = 0.128rad/sec
D because there are 10 gallons of gas remaining as you can see on the y axis and 10 gallons is being used for each 10 miles because 10 x 10 is 100 and the graph is counting up by 10
