Given:
Point B has coordinates (4,1).
The x-coordinate of point A is -4.
The distance between point A and point B is 10 units.
To find:
The possible coordinates of point A.
Solution:
Let the y-coordinate of point A be y. Then the two points are A(-4,y) and B(4,1).
Distance formula:

The distance between point A and point B is 10 units.

Taking square on both sides, we get



Taking square root on both sides, we get



and 
and 
Therefore, the possible coordinates of point A are either (-4,-5) or (-4,7).