A=s^2 50=S^2 s= sqrt50 s=7.071 ms a^2+a^2=c^2 50+50=c^2 100=c^2 c= sqrt100 c=10ms So the answer would be 10 hope this helped
Answer:The value of the bulldozer after 3 years is $121950
Step-by-step explanation:
We would apply the straight line depreciation method. In this method, the value of the asset(bulldozer) is reduced linearly over its useful life until it reaches its salvage value. The formula is expressed as
Annual depreciation expense =
(Cost of the asset - salvage value)/useful life of the asset.
From the given information,
Useful life = 23 years
Salvage value of the bulldozer = $14950
Cost of the new bulldozer is $138000
Therefore
Annual depreciation = (138000 - 14950)/ 23 = $5350
The value of the bulldozer at any point would be V. Therefore
5350 = (138000 - V)/ t
5350t = 138000 - V
V = 138000 - 5350t
The value of the bulldozer after 3 years would be
V = 138000 - 5350×3 = $121950
Answer:
B
Step-by-step explanation:
3p+6p+6p=180°
15p=180
p=12
3p=12×3=36°
6p=12×6=72°
Answer:
y=(x-5)^2-4
Step-by-step explanation:
this is because the -4 drops it below the line and then x-5^2 stays where it is so mainly the minus in the domian and range and the -4 moves it over
Answer:
(75 × 12) + (3 × 580) = 2640
Step-by-step explanation:
