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3 years ago

A rectangle has an area of 30 square meters and a perimeter of 3 meters what are the dimension of the rectangle

Mathematics

1 answer:

Semenov [28]3 years ago

3 0

When we look at the picture, we realize that you copied the problem wrong.
The perimeter is 34 meters, not 3 meters.

The rectangle is <u>15 meters long and 2 meters wide</u>.

The area is (15 x 2) = 30 square meters.

The perimeter is (15 + 2 + 15 + 2) = 43 meters.

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Please answer this question, it would be very helpful

Maru [420]

Answer:

A. 450

Step-by-step explanation:

180 is 40% of the original

450*0.4=180

298*0.4=119.2

240*0.4=96

72*0.4=28.8

so A. 450 is correct

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Butoxors [25]

Answer:

Step-by-step explanation:

Limit refers to the value that the function approaches as the input approaches some value.

We say $\displaystyle \lim_{x\rightarrow a}f(x)=L$ , if f(x) approaches L as x approaches 'a'.

(a)

$\displaystyle \lim_{x\rightarrow 5}\left ( \frac{f(x)-8}{x-5} \right )=4\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-\displaystyle \lim_{x\rightarrow 5}8}{\displaystyle \lim_{x\rightarrow 5}x-\displaystyle \lim_{x\rightarrow 5}5}=4\\$

$\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-8}{\displaystyle \lim_{x\rightarrow 5}x-5}=4\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=4\left ( \displaystyle \lim_{x\rightarrow 5}x-5 \right )\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=4\displaystyle \lim_{x\rightarrow 5}x-4(5)\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=4(5)-4(5)\\$

$\displaystyle \lim_{x\rightarrow 5}f(x)-8=20-20=0\\\displaystyle \lim_{x\rightarrow 5}f(x)=8$

(b)

$\displaystyle \lim_{x\rightarrow 5}\left ( \frac{f(x)-8}{x-5} \right )=7\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-\displaystyle \lim_{x\rightarrow 5}8}{\displaystyle \lim_{x\rightarrow 5}x-\displaystyle \lim_{x\rightarrow 5}5}=7\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-8}{\displaystyle \lim_{x\rightarrow 5}x-5}=7\\$

$\displaystyle \lim_{x\rightarrow 5}f(x)-8=7\left ( \displaystyle \lim_{x\rightarrow 5}x-5 \right )\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=7\displaystyle \lim_{x\rightarrow 5}x-7(5)\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=7(5)-7(5)\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=35-35=0\\\displaystyle \lim_{x\rightarrow 5}f(x)=8$

3 0

3 years ago

What's the best Approximation? :3

musickatia [10]

Area of shaded region = Area of larger circle - Area of smaller circle.

We know, Area of a Circle = πr²
So, A = πr₁² - πr₂²
A = π (r₁² - r₂²)
A = π(10.2² - 5.4²)
A = 3.14 (104.04 - 29.16)
A = 3.14 (74.88)
A = 235.12

In short, Your Answer would be 235.12 cm²

Hope this helps!

3 0

2 years ago