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ElenaW [278]
3 years ago
13

What is the midpoint between (3, -1) and (7, -5)? Group of answer choices

Mathematics
1 answer:
Hatshy [7]3 years ago
6 0

Answer:

The answer is

<h2>( 5 , - 3)</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

<h3>M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(3, -1) and (7, -5)

The midpoint is

M = ( \frac{3 + 7}{2}  , \:  \frac{ - 1 - 5}{2} ) \\  = ( \frac{10}{2}  \: , \:  -  \frac{6}{2} )

We have the final answer as

<h3>( 5 , - 3)</h3>

Hope this helps you

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vlada-n [284]

Answer:

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Step-by-step explanation:

\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8\\y=x+4&\TEXT{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y=-x+8\\-y=-x-4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=-2x+4\qquad\text{add}\ 2x\ \text{to both sides}\\.\qquad2x=4\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8&(1)\\y=x+4&(2)\end{array}\right\\\\\text{Substitute (1) to (2)}\\\\-x+8=x+4\qquad\text{subtract 8 from both sides}\\-x=x-4\qquad\text{subtract}\ x\ \text{from both sides}\\-x-x=-4\\-2x=-4\qquad\text{divide both sides by (-2)}\\\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

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