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gtnhenbr [62]
3 years ago
7

Find the measure of ∠P

Mathematics
2 answers:
finlep [7]3 years ago
7 0

Answer:

To find the third angle of a triangle you can remember that ALL triangles angles add up to 180 degrees, ALWAYS

Step-by-step explanation:

Elenna [48]3 years ago
6 0
To find the third angle of a triangle you can remember that ALL triangles angles add up to 180 degrees, ALWAYS

So that means that p + r + q = 180

r + q = 95

67 + 28 = 95 

So 95 + p = 180

We can subtract 95 from 180 to find what’s left so 180 - 95 = 85

The correct answer would be that the measure of angle p = 85 degrees

Because 28 + 67 + 95 = 180

I hope this helps! Dont forget to thank my answer and mark it as the brainliest if it was the most helpful! <3




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Write the equation of a line that is perpendicular to the given line and that passes through the given point.
katrin2010 [14]
Greetings and Happy Holidays!

<span>1) Perpendicular to </span>-x+5y=14
In order for lines to be perpendicular, their slopes must be negative reciprocals.
Example of slopes with negative reciprocals: 5 and \frac{-1}{5}

First, rearrange the equation into slope y-intercept form:
-x+5y=14

5y=x+14

\frac{5y}{5}=\frac{x+14}{5}

y=\frac{1}{5}x+\frac{14}{5}

The slope of the equation is: \frac{1}{5}

The negative reciprocal formula: (m_{1})(m_{2})=-1

Solve for the negative reciprocal: 
\frac{1}{5}m_{2}=-1

Divide both sides by \frac{1}{5}
\frac{\frac{1}{5}m_{2} }{ \frac{1}{5}} = \frac{-1}{ \frac{1}{5}}

m_{2}=(-1)(\frac{5}{1})

m_{2}=(\frac{-5}{1})

m_{2}=-5

The slope of the new line is: -5

2) Passes through (-5,-2)

Create
an equation with the slope discovered in slope y-intercept form.
y=-5x+b

Input
the point the line passes through.
(-2)=-5(-5)+b

Solve
for b (the y-intercept).
-2=-5(-5)+b

Multiply.
-2=25+b

Add
-25 to both sides.
(-2)+(-25)=b

-27=b

The y-intercept is equal to -27

The Equation of the line is:
y=-5x-27

I hope this helped!
-Benjamin
6 0
4 years ago
There were three quizzes for the week. The first quiz was worth twice as much as the second quiz. The third quiz was 10 points l
iren2701 [21]
X+y+z=70
x=2y
z=2y-10
6 0
3 years ago
You roll a number cube two times. How many outcomes are possible? Please explain work.
MArishka [77]

Answer:

there will be about less times than the cube earns!

Step-by-step explanation:

6 0
4 years ago
Nathan is going to a water park today. He knows that the cost of admission is at least $12 per person. If c stands for the cost
mash [69]
C \geq $12

If the cost c is at least $12 then it could be equal to 12, or could also be a cost greater than $12. So, c is greater than or equal to 12, expressed as <span>c \geq $12</span>
8 0
3 years ago
The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0
3 years ago
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