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kumpel [21]
3 years ago
5

Look at the picture......

Mathematics
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

the coordinates would be (3,6)

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Please help me with this math problem!!!!!​
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Step-by-step explanation:

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Scott works on cars. He charges $35 for each car plus $7 per hour. The total bill was $63. The equation that matches this is 35x
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3 years ago
!!!3 QUESTIONS!!!
RUDIKE [14]

Answer:

1.) He still owes $100 of debt

2.) 1 rose would be .75 cents and 1 carnation would be .90 cents

3.) C 8 and 3/8

Step by Step explanation

(/ means divided by in the first 2 equations but / in the last question is for the fractions.)

1.) _(1,500 / 3 =500. 1,500 - 500 =1,000 / 5 =200 x 3 =600. 700 - 600 =$100)

2.)_(1.50/2 =.75 cents. 2.70/3 =.90 cents.)

3.) i first added the fractions ( i equalized them) then i added the whole numbers (the u in the equation was to separate the whole num. and fraction )

Before i equalized it: (6u3/4 + 1u1/8 = 7u1/8 + 1/8 = 8u3/8)

After i equalized it: (6u6/8 + 1u1/8 = 7u1/8 + 1/8 = 8u3/8)

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
2 years ago
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