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Rina8888 [55]
3 years ago
5

What can you say about the nature of any other zeros of the quadratic equation , which has one complex zero? Explain your answer

.
Mathematics
1 answer:
siniylev [52]3 years ago
7 0
Answer:
There is another complex zero which is a conjugate of the known complex zero.

Explanation:
A quadratic equation s a 2nd order polynomial.

Therefore it can have 2 real zeros or 2 complex zeros.
Because complex zeros always occur as conjugate pairs, there will be another complex zero which is a conjugate of the known complex zero.

For example, if the known complex zero is of the form (a + ib), then the other complex zero is (a - ib), or vice versa.
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Plz help me 8+x^2-11
likoan [24]

Answer:

-3 + x^2

Step-by-step explanation:

8+x^2-11

First combine the like terms.

so..

8-11 = -3

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but we don't know the value of x so we just leave it as it is.

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6 0
3 years ago
Read 2 more answers
Mrs. Gonzales has only $63.50 to spend at a clothing store. She wants to buy a shirt that costs $28, including tax, and some bra
ehidna [41]

Answer:

Mrs. Gonzales can buy a maximum of 7 bracelets.

Step-by-step explanation:

A shirt costs $28 total.

Bracelets cost $4.50 each total.

Mrs. Gonzales has $63.50 in all, assuming she wants to spend all of it.

Set the equation, let bracelets be denoted by the variable, x.

4.50x + 28 = 63.50

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First, subtract 28 from both sides:

4.50x + 28 (-28) = 63.50 (-28)

4.50x = 63.50 - 28

4.50x = 35.50

Next, divide 4.50 from both sides of the equation:

(4.50x)/4.50 = (35.50)/4.50

x = 35.50/4.50

x = ~7.89

However, note that you cannot round up, as you are buying. You also cannot buy .89 of a bracelet, so round down.

x = 7

Mrs. Gonzales can buy a maximum of 7 bracelets.

~

7 0
3 years ago
Read 2 more answers
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Lemur [1.5K]
For parts A, B, C, and D you most likely created a line. What question E is asking is for you to create a line that is perpendicular to the line you already created that also passes through the point (1,1). What is important to understand here is that the slope of the perpendicular line is the negative reciprocal of the original line's slope... if the original slope is (-4/3) than the perpendicular slope is (3/4)... then you should just plug that new slope into point-slope form or slope-intercept form to get your equation... y-y1 = m(x-x1) ... y-1= (3/4)(x-1) ... so it would be y=(3/4)x + 1/4 then for part f just convert into standard form which is just manipulating the variables... look up standard form equation on Google and manipulate the variables from there.
4 0
3 years ago
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