You didn't give us the equation, but circle equations are in the form;
(x-h)^2 + (y-k)^2 =r^2 where h and k are the x and y coordinate of the center and r is the radius of the circle squared.
Hi, can you please put options?
Draw a cartesian plane, create a graph with the equation x = y^2 - 2
then substitute numbers into the equation so that it is true, to find points on the graph, e.g. substitute y with 1, you get
x = 1^2 - 2
x = 1 - 2 = -1, so when y = 1, x = -1, this point is (-1, 1)
for the next substitute y with 2,
x = 2^2 - 2
x = 4 - 2 = 2, the point is (2, 2)
you might want to try negative values of y
y = -1, x = (-1)^2 - 2
x = -1 the point is (-1,-1)
then plot the points on the graph
Answer:[7,2]
Step-by-step explanation:
Step-by-step explanation:
1. when x is 0
y will be
4x+2y=10
4(0)+2y=10
0+2y=10
collect like terms
2y=10-0
2y=10
divide both sides by 2
2y/2=10/2
y=5
so when x =0 y will equal to 5
2. when x is 1
y will be
4x+2y=10
4(1)+2y=10
4+2y=10
collect like terms
2y=10-4
2y=6
divide both sides by two
2y/2=6/2
y=3
so when x is 1, y is 3
3. when x is 2
4x+2y=10
4(2)+2y=10
8+2y=10
(CLT) 2y=10-8
2y =2
y= 1
