Answer:
1. 36 miles
2. 108 miles
3. 234 miles
Step-by-step explanation:
Here we have the Distance in miles, time and calculated speed as follows;
Distance (miles) Elapsed time (hours) Speed (miles/hour)
0 0 0
72 2 36
144 4 36
216 6 36
Distance = Speed (miles/hour) × Elapsed Time (hour)
Therefore, in
1. 1 hour, she travels
1 × 36 = 36 miles
2. 3 hours she travels
3 hours × 36 miles/hour = 108 miles
3. 6.5 hours she travels
6.5 hours × 36 miles/hour = 234 miles.
I would help but Can u add a pic or something for more understanding
Answer: 16
Step-by-step explanation:
Answer:
Subtract the discount price from the full price. Divide the amount of change by the original price.
Step-by-step explanation:
Example: Original price = $40 Sale price = $30
$40-$30= 10
10/40= 1/4
1/4 = .25 or 25%
Answer:
- h = -16t^2 + 73t + 5
- h = -16t^2 + 5
- h = -4.9t^2 + 73t + 1.5
- h = -4.9t^2 + 1.5
Step-by-step explanation:
The general equation we use for ballistic motion is ...

where g is the acceleration due to gravity, v₀ is the initial upward velocity, and h₀ is the initial height.
The values of g commonly used are -32 ft/s², or -4.9 m/s². Units are consistent when the former is used with velocity in ft/s and height in feet. The latter is used when velocity is in m/s, and height is in meters.
_____
Dwayne throws a ball with an initial velocity of 73 feet/second. Dwayne holds the ball 5 feet off the ground before throwing it. (h = -16t^2 + 73t + 5)
A watermelon falls from a height of 5 feet to splatter on the ground below. (h = -16t^2 + 5)
Marcella shoots a foam dart at a target. She holds the dart gun 1.5 meters off the ground before firing. The dart leaves the gun traveling 73 meters/second. (h = -4.9t^2 + 73t + 1.5)
Greg drops a life raft off the side of a boat 1.5 meters above the water. (h = -4.9t^2 + 1.5)
_____
<em>Additional comment on these scenarios</em>
The dart and ball are described as being launched at 73 units per second. Generally, we expect launches of these kinds of objects to have a significant horizontal component. However, these equations are only for <em>vertical</em> motion, so we must assume the launches are <em>straight up</em> (or that the up-directed component of motion is 73 units/second).