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Ilya [14]
3 years ago
9

HERE I AM AGAIN, HELPPPPP ILL GIVE BRAINLIEST <3

Mathematics
2 answers:
nikklg [1K]3 years ago
6 0

Answer:

For number three I think the blank represents 1.25

Step-by-step explanation:

<em><u>For the third one:</u></em>

I named the answer / total as x

-x - 2.25 = x

-x + 2.5 + 2.5 = x + 2.5

Simplifying it would give 1.25

(I'm unsure for the answer but I tried!)

HOPE THIS HELPS!!

fredd [130]3 years ago
5 0
it equals 2.75 because 2 negatives means you add
You might be interested in
If there are 12 crayons in each box, how many crayons are<br> there in 1 1/2 boxes?
ipn [44]
There are 18 crayons


Explanation:
1 whole = 12 crayon
1/2 of 12 is 6
12+6=18
4 0
2 years ago
A rectangular paperboard measuring 29in long and 20in wide has a semicircle cut out of it, as shown below.
katen-ka-za [31]

Here, we are required to find the area of the paper board given after the semicircle is cut out of it

Area of the paper board thatremains is 423 in²

Length = 29 in

Width = 20 in

Area of a rectangle = length × width

= 29 in × 20 in

= 580 in²

Area of a semi circle = πr²/2

π = 3.14

r = diameter / 2 = 20 in / 2 = 10 in

Area of a semi circle = πr²/2

= 3.14 × (10 in)² / 2

= 3.14 × 100 in² / 2

= 314 in²/2

= 157 in²

The semicircle is cut out of the rectangle

Find the area of the paper board that remains after the semicircle is cut out of it by subtracting the area of a semi circle from the area of a rectangle

Area of the paper board that remains = Area of a rectangle - Area of a semi circle

= 580 in² - 157 in²

= 423 in²

brainly.com/question/16994941

6 0
3 years ago
Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui
Vesnalui [34]
<h3>The dimensions of the given rectangular box are:</h3><h3>L  =   15.874 cm  , B  =  15.874 cm   , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box  

= Area of the base +  4 x ( Area of the adjacent faces)

=  S x S  +  4 ( S x H)   = S² +  4 SH   ..... (1)

Also, Area of the box  = S x S x H  =  S²H

⇒ S²H = 2000

\implies H = \frac{2000}{S^2}

Substituting the value of H in (1), we get:

A = S^2 + 4 SH =  S^2 + 4 S(\frac{2000}{S^2}) =  S^2 + (\frac{8000}{S})\\\implies A  =  S^2 + (\frac{8000}{S})

Now, to minimize the area put :

(\frac{dA}{dS} ) = 0 \implies 2S  - \frac{8000}{S^2}  = 0\\\implies S^3 = 4000\\\implies S  = 15.874 \approx 16 cm

Putting the value of S  = 15.874 cm in the value of H , we get:

\implies H = \frac{2000}{S^2}  =  \frac{2000}{(15.874)^2} = 7.8937 cm

Hence, the dimensions of the given rectangular box are:

L  =   15.874 cm

B  = 15.874 cm

H = 7.8937 cm

3 0
3 years ago
The best or first answer will be marked brainliest
Marysya12 [62]

Answer:

Need more infomation to write the equation.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How many meters is one centimeter cubed? Also, how many meters cubed are in one liter?
enot [183]
1 m = 100 cm
1 m^3 = 1^6 cm^3


so 1 cm^3 = 10^-6 m^3

and 1 L = 1000 cm^3 = 10^-3 m^3
7 0
3 years ago
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