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AVprozaik [17]
3 years ago
9

Three friends each have some ribbon. Carol has 54 inches of ribbon, Tino has 4.5 feet of ribbon, and Baxter has 6.5 yards of rib

bon. Express the total length of ribbon the three friends have in inches, feet, and yards.
Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
8 0
What grade you in ???
Monica [59]3 years ago
4 0
Carol : 54 inches
Tino : 4.5 ft......1 ft = 12 inches...so 4.5 ft = 12* 4.5 = 54 inches
Baxter : 6.5 yds...1 yd = 36 inches.....so 6.5 yds = 6.5 * 36 = 234 inches

total : 54 + 54 + 234 = 342 inches <==
          342 / 12 = 28.5 ft <==
          342 / 36 = 9.5 yds <==
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The following three shapes are based only on squares, semicircles, and quarter circles. Find the perimeter and the area of each
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When we divide the figure in four parts, we obtain four squares with its sides of 5 centimeters of lenght, with quarter circles (two) in each one of them. The limits of the shadded area are arcs of cirncunference

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 a: the area below the shaded area.
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 The area of a circunference is: A=πR² (R:radio), but we want the area of the quarter circle, so we must use A=1/4(πR²), to calculate the area of the sectors a+c:
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 The area of the sector "b" is:
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 Ab=25-25π/4
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 The area of the sector a+b, is:
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 A(a+b)=2x25(1-π/4)
 A(a+b)=50(1-π/4)

 Then, the shadded area (Sector c) is:
 Ac=As-A(a+b)
 Ac=25-50(1-π/4)
 Ac=25-(50-50π/4)
 Ac=25-50+50π/4
 Ac=(50π/4)-25
 Ac=(25π/2)-25
 Ac=25(π/2-1)

 The area of each shaded part is: 25(π/2-1)

 To calculate the perimeter of a shaded part, we must remember that the perimeter of a circunference is: P=2πR. If we want the perimeter of a quarter circle we must use: P= 2πR/4. But there is two quarter circles in the square of 5cmx5cm, so the perimeter of the shaded area is:

 P=2(2πR/4)
 P=4πR/4
 P=πR
 P=5π

 The perimeter of each shaded part is: 5π
 
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rita finished her chemistry assignment in 7/8 hours. Then she completed her math assignment in 1/4 hours. How much more time did
Svetllana [295]

Answer:

Rita spend \frac{5}{8} of hour more on her chemistry assignment.

Step-by-step explanation:

Fraction of an hour Rita spent on chemistry assignment = \frac{7}{8}

Fraction of an hour Rita spent on math assignment = \frac{1}{4}

∴ Fraction of  hour Rita spent more on her chemistry assignment than math assignment

⇒  \frac{7}{8}-\frac{1}{4}

To subtract fractions we take LCD for 4 and 8. Since 8 is the least common multiple for 4 and 8 so, we take LCD= 8

To make the denominators same we need to multiply numerator and denominator of second fraction with 2.

⇒ \frac{7}{8}-\frac{1\times2}{4\times2}

⇒ \frac{7}{8}-\frac{2}{8}

After making the denominators common, we simply subtract numerators.

⇒ \frac{7-2}{8}

⇒ \frac{5}{8}

Therefore, Rita spend \frac{5}{8} of hour more on her chemistry assignment.

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3 years ago
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