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Dafna11 [192]
3 years ago
13

The function v(r) =4/3 3far can be used to find the volume of air inside a basketball given its radius. What does V(T)

Mathematics
1 answer:
melisa1 [442]3 years ago
3 0

Answer:

B

Step-by-step explanation:

The correct answer is B

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PLSS HELP ME FIND THE SURFACE AREA OF THE TRIANGULAR PRISM <br><br> THXXSSSS AND HURRY PLS
aleksley [76]

Answer:

108m^2

Step-by-step explanation:

surface area of any shape: sum of the area of its sides.

area of cross section x 2 = 4 x 3 12 m^2

area of slope:  5m x 8m = 40m^2

area of base: 8 X 3 = 24 m^2

area of back: 8m x 4m = 32m^2

sum = surface area = 108m^2

Please mark brainiest

5 0
3 years ago
six college buddies bought each other christmas gifts. they spent $261.12 $120.52 $186.23, $298.97 $171.55 $263.93
kykrilka [37]
The answer is 1,302.32
3 0
3 years ago
Read 2 more answers
Cassie is a half pound of sugar in her cabinet her cake recipe calls for two tenths of a pound of sugar how many cakes can she m
mamaluj [8]
The information's given in the question should be very minutely checked. Based on those given information's the answer to the question can easily be deduced.
Amount of sugar in the cabinet of Cassie = 1/2 pound
Amount of sugar required by Cassie to make her cake recipe = 2/10 pound
                                                                                                   = 1/5 pounds
Then
The number of cakes that Cassie can make = (1/2)/(1/5)
                                                                        = 5/2
                                                                        = 2 1/2
So from the above deduction we can easily conclude that Cassie can make a total of 2 cakes with the sugar she has and there will still be some sugar left.
7 0
3 years ago
Convert each mixed number to an improper fraction
Pani-rosa [81]

Answer:

43/8

Step-by-step explanation:

5 x 8 = 40

40 + 3 =43

6 0
3 years ago
find the spectral radius of A. Is this a convergent matrix? Justify your answer. Find the limit x=lim x^(k) of vector iteration
Natasha_Volkova [10]

Answer:

The solution to this question can be defined as follows:

Step-by-step explanation:

Please find the complete question in the attached file.

A = \left[\begin{array}{ccc} \frac{3}{4}& \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2}& 0\\ -\frac{1}{4}& -\frac{1}{4} & 0\end{array}\right]

now for given values:

\left[\begin{array}{ccc} \frac{3}{4} - \lambda & \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2} - \lambda & 0\\ -\frac{1}{4}& -\frac{1}{4} & 0 -\lambda \end{array}\right]=0 \\\\

\to  (\frac{3}{4} - \lambda ) [-\lambda (\frac{1}{2} - \lambda ) -0] - 0 - \frac{1}{4}[0- \frac{1}{2} (\frac{1}{2} - \lambda )] =0 \\\\\to  (\frac{3}{4} - \lambda ) [(\frac{\lambda}{2} + \lambda^2 )] - \frac{1}{4}[\frac{\lambda}{2} -  \frac{1}{4}] =0 \\\\\to  (\frac{3}{8}\lambda + \frac{3}{4} \lambda^2 - \frac{\lambda^2}{2} - \lambda^3 - \frac{\lambda}{8} + \frac{1}{16}=0 \\\\\to (\lambda - \frac{1}{2}) (\lambda -\frac{1}{4}) (\lambda - \frac{1}{2}) =0\\\\

\to \lambda_1=\lambda_2 =\frac{1}{2}\\\\\to \lambda_3 = \frac{1}{4} \\\\\to A = max {|\lambda_1| , |\lambda_2|, |\lambda_3|}\\\\

       = max{\frac{1}{2}, \frac{1}{2}, \frac{1}{4}}\\\\= \frac{1}{2}\\\\(A) =\frac{1}{2}

In point b:

Its  

spectral radius is less than 1 hence matrix is convergent.

In point c:

\to c^{(k+1)} = A x^{k}+C \\\\\to x(0) =   \left(\begin{array}{c}3&1&2\end{array}\right)  , c = \left(\begin{array}{c}2&2&4\end{array}\right)\\\\  \to x^{(k+1)} =  \left[\begin{array}{ccc} \frac{3}{4}& \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2}& 0\\ -\frac{1}{4}& -\frac{1}{4} & 0\end{array}\right] x^k + \left[\begin{array}{c}2&2&4\end{array}\right]  \\\\

after solving the value the answer is

:

\lim_{k \to \infty} x^k=o  = \left[\begin{array}{c}0&0&0\end{array}\right]

4 0
3 years ago
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