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3 years ago

My brothers and sister, i need help asap

Mathematics

1 answer:

exis [7]3 years ago

8 0

Answer:

Step-by-step explanation: 3 or 4th option

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The scale of a map is 1 cm: 77 km.

laiz [17]

$\bf \stackrel{map}{1~cm}\qquad :\qquad \stackrel{actual}{77~km}\qquad \cfrac{map}{actual}=\cfrac{1}{77}~\hfill \cfrac{\stackrel{map}{3}}{\underset{actual}{a}}=\cfrac{1}{77}\implies 231=a$

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3 years ago

What is 1/10th of 2,871,000?

abruzzese [7]

This is fairly simple. Divide 2,871,000 by 10 and that's your answer!

$\frac{2,871,000}{10} =287,100$

Also, since you're dividing by a factor of 10 (or in this case, 10) you can just take away as many places as are zeros in the number you're dividing from. This works for 10, 100, 1,000, 10,000, etc. In this case, since there is only one zero in 10 you only take away one place marking, which gives you 287,100.

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3 years ago

Dannielle's test grades are 83, 92, 99, 86 and 90. What is the median of her grades?

Butoxors [25]

Answer: 90

Step-by-step explanation:

83, 86, 90, 92, 99

90 is in the middle <3

5 0

3 years ago

A. f(x) = l-2xl - 3 Domain: {1, 2, 3} Find the range

gizmo_the_mogwai [7]

Hello there!

We are given the function:

$\displaystyle \large{ f(x) = | - 2x| - 3} \\$

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

x = 1

$\displaystyle \large{ f(1) = | - 2(1)| - 3} \\ \displaystyle \large{ f(1) = | - 2| - 3} \\$

Recall that any numbers in absolute value are always positive.

$\displaystyle \large{ f(1) = 2 - 3} \\ \displaystyle \large{ f(1) = - 1} \\$

x = 2

$\displaystyle \large{ f(2) = | - 2(2)| - 3} \\ \displaystyle \large{ f(2) = | - 4 | - 3} \\ \displaystyle \large{ f(2) = 4 - 3} \\ \displaystyle \large{ f(2) = 1}$

x = 3

$\displaystyle \large{ f(3) = | - 2(3)| - 3} \\ \displaystyle \large{ f(3) = | - 6| - 3} \\ \displaystyle \large{ f(3) = 6 - 3} \\ \displaystyle \large{ f(3) = 3}$

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

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3 years ago

On a piece of paper, graph the system of equations. Y=x-2 y=x^2-6x+8

pantera1 [17]

Answer: C

Step-by-step explanation: graph both equations and see where they intersect. Use desmos.com/calculator

4 0

3 years ago

Read 2 more answers