Answer:
The answer are (a) measurement on ordinary scale can be ranked, but on nominal scale observation cannot be ranked, (b) on the interval scale measurement can be compared in terms of difference of magnitude, but on ordinary scale, observations cannot be compared in terms of magnitude (c) the point of zero is arbitrary and can be found in any where on the measurement of interval scale
Step-by-step explanation:
Explanation
(a) In nominal scale measurement, observations are classified but in ordinal scale measurement observations are ranked
Therefore additional information of comparing ranking in observation when measurement are gotten from ordinary scale as compared to nominal measurement.
(b) In interval scale measurement can be compared by different magnitude because it is ranked, while ordinary scale measurement, observation can be ranked for comparison
For example the grade of student in a school are grouped under the ordinary scale of measurement due to the fact that Grade A is greater than B
Therefore we have extra information of contrasting observations based on magnitude differences when measurement are gotten form interval scale as against ordinary scale
(c) In the interval scale of measurement, observations are compared in terms of magnitude differences. the point of zero is arbitrary and can found anywhere
For example if a person has no salary what this means is that he has rupes of zero (salary)
Then again, the additional information of the zero point of arbitrary is when measurement is gotten from interval scale. what this suggest is that none is in the scale of ratio
The first part is "increasing" the second part is "four"
The options for the first part were "increasing" and "decreasing"
The options for the second part were "two" and four"
Hope I helped.
Given:
A line passes through the points (-6, 8) and (-16, 33).
To find:
The slope of the line.
Solution:
If a line passes through two points, then the slope of the line is
The line passes through the points (-6, 8) and (-16, 33). Using the above formula, the slope of the line is
Therefore, the slope of the line is -2.5.
Isolate the y for both questions. Note that what you do to one side, you do to the other. Do the opposite of PEMDAS.
First question: x - 5y ≥ 3
First, subtract x from both sides
x (-x) - 5y ≥ 3 (-x)
-5y ≥ -x + 3
Divide -5 from both sides. Note that when you divide by a negative number, you flip the equation.
(-5y)/-5 ≥ (-x + 3)/-5
y ≤ (-x + 3)/-5
y ≤ x/5 - 0.6
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Do the same for the second one. Subtract x from both sides
x + y < 0
x (-x) + y < 0 (-x)
y < - x
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